Find an equation of the plane that passes through the point (-1,1/2,3) with normal vector [1,4,1]
1 answer:
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<h2>Answer: slope = ¹¹/₁₃
</h2><h3>Step-by-step explanation: </h3>
The question gives us two points, (−13, −19) & (13, 3), from which we can find the slope and later the equation of the line.
Finding the Slope
The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)
= ((3 - (-19)) ÷ (13 - (-13))
= 22 ÷ 26
= ¹¹/₁₃
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<em>Checking my answer:</em>
<em>We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line. If the line passes through both of the points then we calculated the slope correctly.</em>
⇒ y + 19 = ¹¹/₁₃ (x + 13)
<em>I have included a Desmos Graph that I graphed using the information equation (including the slope) and the points given. </em>