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Brrunno [24]
3 years ago
6

Eric was rock climbing. At one point, he stopped and climbed straight down 2\dfrac{1}{2}2 2 1 ​ 2, start fraction, 1, divided by

, 2, end fraction meters. Then he climbed straight up 6\dfrac{3}{4}6 4 3 ​ 6, start fraction, 3, divided by, 4, end fraction meters. Eric was wondering what his change in elevation was after these two moves.
Mathematics
1 answer:
podryga [215]3 years ago
4 0

Answer:

Hence, Eric's elevation changed 4\frac{1}{4} meters above. So after the 2 moves, he is up by 4\frac{1}{4} meters.

Step-by-step explanation:

Let us assume "negative" as climbing up and  "positive" as climbing up. Here we need to find the change in elevation.

  1. 2\frac{1}{2} meters down means -2\frac{1}{2}.
  2. 6\frac{3}{4} meters up means +6\frac{3}{4}.

Now we have:  

=-2\frac{1}{2} + 6\frac{3}{4}\\\\=-\frac{5}{2} +\frac{27}{4} \\\\=\frac{-5(2)+27}{4} \\\\=\frac{-10+27}{4} \\\\=\frac{17}{4} = 4\frac{1}{4}

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Answer: Kayla used 2 5/24 cups of paint all together.

Step-by-step explanation:

Kayla paints a bookcase by using

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She also used 3/8 cup of paint on the inside.

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Answer:

X \sim N(114.8,13.1)  

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We are interested on this probability

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And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

And we can find this probability using the complement rule:

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(114.8,13.1)  

Where \mu=114.8 and \sigma=13.1

We are interested on this probability

P(X>140)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

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