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Brrunno [24]
2 years ago
6

Eric was rock climbing. At one point, he stopped and climbed straight down 2\dfrac{1}{2}2 2 1 ​ 2, start fraction, 1, divided by

, 2, end fraction meters. Then he climbed straight up 6\dfrac{3}{4}6 4 3 ​ 6, start fraction, 3, divided by, 4, end fraction meters. Eric was wondering what his change in elevation was after these two moves.
Mathematics
1 answer:
podryga [215]2 years ago
4 0

Answer:

Hence, Eric's elevation changed 4\frac{1}{4} meters above. So after the 2 moves, he is up by 4\frac{1}{4} meters.

Step-by-step explanation:

Let us assume "negative" as climbing up and  "positive" as climbing up. Here we need to find the change in elevation.

  1. 2\frac{1}{2} meters down means -2\frac{1}{2}.
  2. 6\frac{3}{4} meters up means +6\frac{3}{4}.

Now we have:  

=-2\frac{1}{2} + 6\frac{3}{4}\\\\=-\frac{5}{2} +\frac{27}{4} \\\\=\frac{-5(2)+27}{4} \\\\=\frac{-10+27}{4} \\\\=\frac{17}{4} = 4\frac{1}{4}

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