Question

$10,000 is compounded quarterly at 12% interest for t years. what expression represents the amount of money after t years.

Answer 1

we know that  

The compound interest formula is equal to  

$A=P(1+\frac{r}{n})^{nt}$  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

$t=t\ years\\ P=\ 10,000\\ r=0.12\\n=4$  

substitute in the formula above  

$A=10,000(1+\frac{0.12}{4})^{4t}$  

$A=10,000(1+0.03)^{4t}$  

$A=10,000(1.03)^{4t}$  

therefore

the answer is

$A=10,000(1.03)^{4t}$  

Answer 2

A=p(1+i/k)^k*t
A=10000(1+0.12/4)^4*t
A=10000(1.03)^4t