Question

1. How many moles of nitrogen monoxide can be made using 5.0 moles of oxygen in

Answer 1

Answer:

1. 10 moles of NO

2. 25 moles of NaCl

3. 1200 moles CO₂

4. 1.042 mole of MgO

5. 0.714 moles H₂ gas

6. 1040 g of BaCl₂

7. 9.5 g

8. 45.44 g of Au

9. 15 g of AlCl₃

Explanation:

Ans 1.

Data Given:

moles of Oxygen = 5 moles

moles of nitrogen monoxide = ?

Solution:

To solve this problem we have to look at the reaction

Reaction:

              N₂   +   O₂  -----------> 2NO

                        1 mol                 2 mol

So if we look at the reaction  1 mole Oxygen (O₂)  gives 2 moles of nitrogen monoxide NO, then how many moles of nitrogen monoxide will be produced by 5 moles of Oxygen (O₂)

For this apply unity formula

               1 mole of O₂ ≅ 2 moles of NO

               5 mole of O₂ ≅ X moles of NO

By Doing cross multiplication

           moles of NO = 2 moles x 5 moles / 1 mole

           moles of NO = 10 mole

5 mole of O₂ will produce 10 moles of NO

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Ans 2.

Data Given:

moles of HCl = 25 moles

moles of NaCl = ?

Solution:

To solve this problem we have to look at the reaction

Neutralization Reaction:

              HCl   +   NaOH  -----------> NaCl + H₂O

            1 mol                                     1 mol

So if we look at the reaction  1 mole  HCl  gives 1 moles of NaCl, then how many moles of NaCl will be formed by 25 moles of HCl  

For this apply unity formula

               1 mole of HCl ≅ 1 moles of NaCl

               25 mole of HCl ≅ X moles of NaCl

By Doing cross multiplication

           moles of NaCl = 1 moles x 25 moles / 1 mole

           moles of NaCl = 25 mole

25 mole of HCL will form 25 moles of NaCl

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Ans 3.

Data Given:

moles of C₈H₁₈ = 150 moles

moles of CO₂= ?

Solution:

To solve this problem we have to look at the reaction

Reaction:

              2C₈H₁₈   +  25O₂  -----------> 16CO₂ + 18H₂O

              2 mol                                     16 mol

So if we look at the reaction  2 mole C₈H₁₈ gives 16 moles of CO₂, then how many moles of CO₂ will be Produce by 150 moles of C₈H₁₈  

For this apply unity formula

               2 mole of C₈H₁₈ ≅ 16 moles of CO₂

               150 mole of C₈H₁₈ ≅ X moles of CO₂

By Doing cross multiplication

           moles of CO₂= 16 moles x 150 moles / 2 mole

           moles of CO₂ =  1200 mole

150 mole of C₈H₁₈ will form 1200 moles of CO₂

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Ans 4.

Data Given:

mass of Mg = 25 g

moles of MgO= ?

Solution:

To solve this problem we have to look at the reaction

Reaction:

             2Mg + O₂  -----------> 2MgO

             2 mol                        2 mol

Convert moles of Mg to mass

Molar mass of Mg = 24 g/mol

So,

                    2Mg        +       O₂  ----------->     2MgO

             2 mol (24 g/mol)                             2 mol

                     48 g                                          2 mol

So if we look at the reaction 48 g of Mg gives 2 moles of MgO, then how many moles of MgO will be Produce by 25 g of Mg

For this apply unity formula

               48 g of Mg ≅ 2 moles of MgO

               25 g of Mg ≅ X moles of MgO

By Doing cross multiplication

           moles of MgO =  2 moles x 25 g / 48 g

           moles of MgO = 1.042 mole

25 g of Mg will form 1.042 moles of MgO

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Ans 5.

Data Given:

mass of Li = 10 g

moles of H₂= ?

Solution:

To solve this problem we have to look at the reaction

Reaction:

             2Li + 2 H₂O  -----------> 2LiOH  +  H₂

             2 mol                                           1 mol

Convert moles of Li to mass

Molar mass of Li = 7 g/mol

So,

                    2Li      +       2H₂O  -----------> 2LiOH  +  H₂

             2 mol (7 g/mol)                                            1 mol

                  14 g                                                          1 mol

So if we look at the reaction 14 g of Li gives 1 moles of H₂ gas, then how many moles of H₂ gas will be Produce by 10 g of Li

For this apply unity formula

               14 g of Li ≅ 1 moles of H₂

               10 g of Li ≅ X moles of H₂

By Doing cross multiplication

           moles of H₂ =  1 moles x 10 g / 14 g

           moles of H₂ = 0.714 mole

10 g of Li will form 0.714 moles of H₂

______________________

Ans 6.

Data Given:

moles of Na₂SO₄= 5 moles

mass of BaCl₂ = ?

Solution:

To solve this problem we have to look at the reaction

Reaction:

             Na₂SO₄ + BaCl₂  -----------> 2NaCl + BaSO₄

           1 mol            1 mol

Convert moles of BaCl₂ to mass

Molar mass of BaCl₂ = 208 g/mol

So,

              Na₂SO₄    +        BaCl₂  -----------> 2NaCl + BaSO₄

              1 mol            1 mol (208 g/mol)                            

              1 mol                   208 g                                          

So if we look at the reaction 1 mole of Na₂SO₄ react with 208 g of BaCl₂, Then how many grams of  BaCl₂ will react with 5 moles of Na₂SO₄

For this apply unity formula

               1 mole of Na₂SO₄ ≅ 208 g of BaCl₂

                5 mole of Na₂SO₄≅ X g of BaCl₂

By Doing cross multiplication

           mass of BaCl₂ =  208 g x  5 moles / 1 mole

           mass of BaCl₂ = 1040 g

5 moles of Na₂SO₄ will react with 1040 g of BaCl₂

______________________

Ans 7.

Data Given:

mass of MgCO₃ = 20 g

moles of MgO= ?

Solution:

To solve this problem we have to look at the reaction

Reaction:

MgCO₃ -----------> MgO + CO₂

1 mol                     1 mol

Convert moles to mass

Molar mass of MgCO₃ = 84 g/mol

Molar mass of MgO = 40 g/mol

So,

         MgCO₃      ------------->    MgO        +       CO₂

1 mol (84 g/mol)                 1 mol (40 g/mol)

      84 g                                     40 g

So if we look at the reaction 84 g of MgCO₃ gives 40 g of MgO, then how many g of MgO will be Produce by 20 g of MgCO₃

For this apply unity formula

                84 g of MgCO₃ ≅ 40 g of MgO

               20 g of MgCO₃ ≅ X g of MgO

By Doing cross multiplication

             mass of MgO = 40 g x 20 g / 84g

            mass of MgO = 9.5 g

20 g of MgCO₃ will produce 9.5 g of MgO

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