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2 years ago

N2 + 3H2 - 2NH3

Chemistry

1 answer:

vladimir1956 [14]2 years ago

4 0

The number of mole of nitrogen gas, N₂, needed to produce 150 g of ammonia, NH₃ is 4.41 moles

<h3>How to determine the mole of NH₃ produced </h3>

Mass of NH₃ = 150 g
Molar mass of NH₃ = 14 + (3×1) = 17 g/mol

Mole of NH₃ =?

Mole = mass /molar mass

Mole of NH₃ = 150 / 17

Mole of NH₃ = 8.82 moles

<h3>How to determine the mole of N₂ needed </h3>

Balanced equation

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

2 moles of NH₃ were produced by 1 mole of N₂.

Therefore,

8.82 moles of NH₃ will be produced by = 8.82 / 2 = 4.41 moles of N₂.

Thus, 4.41 moles of N₂ is needed for the reaction.

Learn more about stoichiometry:

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Yoshi divided the mass of a rubber stopper by its volume. Using this calculation, Yoshi found the

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B. Density

Density = mass/volume because it’s basically the concentration of mass. How much matter takes up the space. If you pack more matter into less space, it is more dense.

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3 years ago

When of a certain molecular compound X are dissolved in of benzene , the freezing point of the solution is measured to be . Calc

puteri [66]

The question is incomplete. Here is the complete question.

When 2.10 g of a certain molecular compound X are dissolved in 65.0 g of benzene (C₆H₆), the freezing point of the solution is measured to be 3.5°C. Calculate the molar mass of X. If you need any additional information on benzene, use only what you find in the ALEKS Data resource. Also, be sure your answer has a unit symbol, and is rounded to 2 significant digits.

Answer: MM = 47.30 g/mol.

Explanation: There is a relationship between freezing point depression and molality. With this last one, is possible to calculate molar mass or molar weight of a compound.

Freezing Point Depression occurs when a solute is added to a solvent: the freezing point of the solvent decreases when a non-volatile solute is incremented.

Molality or molal concentration is a quantity of solute dissolved in a certain mass, in kg, of solvent. Its symbol is m and it's defined as

$m=\frac{moles(solute)}{kg(solvent)}$

Freezing point depression and molal are related as the following:

$\Delta T_{f}=K_{f}.m$

where

$\Delta T_{f}$ is freezing point depression of solution

$K_{f}$ is molal freezing point depression constant

m is molality

Now, to determine molar mass, first, find molality of the mixture:

$\Delta T_{f}=K_{f}.m$

$m=\frac{\Delta T_{f}}{K_{f}}$

For benzene, constant is 5.12°C/molal. Then

$m=\frac{3.5}{5.12}$

m = 0.683 molal

Second, knowing the relationship between molal and moles of solute, determine the last one:

$m=\frac{moles(solute)}{kg(solvent)}$

$mol(solute)=m.kg(solvent)$

mol(solute) = 0.683(0.065)

mol(solute) = 0.044 mol

The definition for Molar mass is the mass in grams of 1 mol of substance:

$n(moles)=\frac{m(g)}{MM(g/mol)}$

$MM=\frac{m}{n}$

In the mixture, there are 0.044 moles of X, so its molecular mass is

$MM=\frac{2.1}{0.044}$

MM = 47.30 g/mol

The molecular compound X has molecular mass of 47.30 g/mol.

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3 years ago

A mole of ethyl alcohol weighs 46 g. how many grams of ethyl alcohol are needed to produce 1 l of a 2-millimolar (2 mm) solution

Thepotemich [5.8K]

Answer: 92mg of ethyl alcohol

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4 years ago

Compound decomposes through the following unbalanced reaction in acidic media: MnO2→ MnO4-(s) + Mn2+(s) Balance this reaction an

choli [55]

Answer:

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Explanation:

If we write the semi equations (this is, for reduction and oxidation) we will have:

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Then the final global reaction (just adding the two above hemi chemical reactions):

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So, we have Mn⁺⁴ (from MnO₂) goes to Mn⁺⁷ and Mn⁺² (this is, Mn is oxidated) and H⁺ (from acidic media or H₂O) goes to H₂ (this is, it is reduced). So the reducing agent would be MnO₂

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4 years ago

What is the systematic name of mg(no3)2

Oksi-84 [34.3K]

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4 years ago

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