Answer:
Theoretical yield: 36,3g
Percent yield: 71,9%
Explanation:
The reaction of tert-butyl alcohol with hydrobromic acid to produce tert-butyl bromide is a 1:1 reaction.
Moles of tert-butyl alcohol in 25,0 mL are:
25,0mL × (0,786g / mL) × (1mol / 74,12g) = <em><u>0,265 moles of tert-butyl alcohol</u></em>
Moles of hydrobromic acid are:
60,0mL× 47,0% × (1,49g / mL) × (1mol / 80,91g) = <em><u>0,519 moles of HBr</u></em>
As moles of tert-butyl alcohol are less than moles of HBr, limiting reactant is tert-butyl alcohol.
Theoretical yield of tert-butyl bromide in grams is:
0,265 moles × (137,02g / 1mol) = <em>36,3g</em>
Percent yield:
26,1g / 36,3g × 100 = <em>71,9%</em>
The reactions are in the image.
There are many ways to produce alkyl halides from primary and secondary alcohols. The reaction in this case is the Appel reaction.
The reaction of tertiary alkyl halides may undergo a hydrolysis reaction -under proper conditions- to form an alcohol and a hydrogen halide.
I hope it helps!
