Water is known as a life-giving liquid because every living organism depends on the water for its survival.
<h3>Journal about the topic Water-The Life Giving Liquid</h3>
Water is also called a life-giving liquid because without water life on earth is not possible. All other living organisms need to consume water to survive and grow in size. We need water for many other activities such as cleaning, washing, cooking and irrigation. Water is essential for all living things including humans, animals and plants. Water is called wonder liquid as it can dissolve large number of substances. This property enables water to be a great solvent. Most of the chemical reactions of the living world is carried out in water as a medium so that's why water is known as Life Giving Liquid.
So we can conclude that Water is known as a life-giving liquid because every living organism depends on the water for its survival.
Learn more about water here: brainly.com/question/1313076
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Answer:
Explanation:
<u>1) Data:</u>
- T₁ = 25°C = 25 + 273.15 K = 298.15 K
- T₂ = 20°C = 20 + 273.15 K = 293.15 K
<u>2) Formula:</u>
Used combined law of gases:
<u>3) Solution</u>:
Solve the equation for V₂:
Substitute and compuite:
- V₂ = 98.7 KPa × 10.0 L × 293.15 K / (102.7 KPa × 298.15 K)
You can learn more about gas law problems reading this other answer on Brainly: brainly.com/question/12732788.
Answer: The mass of the nucleus is less than the mass of the 8 protons and 8 neutrons.
Explanation:
The answer is power rating
Answer:
12.07 g.
Explanation:
- The balanced equation for the mentioned reaction is:
<em>2NH₃(g) + CO₂(g) → H₂NCONH₂(g) + H₂O(g),</em>
It is clear that 2.0 moles of NH₃ react with 1.0 mole of CO₂ to produce 1.0 mole of H₂NCONH₂ and 1.0 moles of H₂O.
- Consider the reaction proceeds at STP conditions:
At STP, 9.0 L of NH₃ react with an excess of CO₂ gas:
It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.
<u><em>using cross multiplication:</em></u>
1.0 mol of NH₃ represents → 22.4 L.
??? mol of NH₃ represents → 9.0 L.
∴ 9.0 L of NH₃ represents = (1.0 mol)(9.0 L)/(22.4 L) = 0.4018 mol.
- To find the no. of moles of urea (H₂NCONH₂) produced:
<u><em>Using cross multiplication:</em></u>
2.0 mol of NH₃ produce → 1.0 mol of H₂NCONH₂, from stichiometry.
0.4018 mol of NH₃ produce → ??? mol of H₂NCONH₂.
∴ The no. of moles of H₂NCONH₂ = (1.0 mol)(0.4018 mol)/(2.0 mol) = 0.201 mol.
- Now, we can find the mass of H₂NCONH₂ produced:
<em>mass = n * molar mass</em> = (0.201 mol) * (60.06 g/mol) = <em>12.07 g.</em>
