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3 years ago

Geometry... Please help and I'll mark brainliest. Triangle proofs & reasons

Mathematics

1 answer:

Virty [35]3 years ago

3 0

Answer:

See Explanation

Step-by-step explanation:

$\overline{FH} \: bisects \: \angle EHG... (given) \\\\In\: \triangle FEH \: and\:\triangle FGH\\\\\angle FEH\cong\angle FGH.. (given) \\\\\angle EHF\cong\angle GHF\\(\because \overline{FH} \: bisects \: \angle EHG) \\\\\overline{FH} \cong \overline{FH}...(common)\\ \\ \therefore \triangle FEH \cong\triangle FGH(AAS \: Postulate)$

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A football team was training for four hours. During the first hour, they practiced for 5/8 of an hour. During the second hour, t

Leviafan [203]

Answer: 2 19/24 hours was spent in practising.

Step-by-step explanation:

During the first hour, they practiced for 5/8 of an hour. During the second hour, they practiced for 2/3 of an hour. This means that the total time for which they practiced in the first 2 hours would be

5/8 + 2/3 = 31/24 hours

During the last two hours, they first practiced for 3/5 of an hour, took a 1/2 hour break and then practiced the rest of the time. This means that the rest of the time for which they practiced is

2 - (3/5 + 1/2) = 2 - 11/10 = 9/10

Therefore, the time they spent practicing in total would be

31/24 + 3/5 + 9/10 = 67/24 =

2 19/24 hours

7 0

3 years ago

Someone please help me on these 2 problems!

Veronika [31]

1) function 2) not a function

the first one is a function because its y values are the same number (3), which means it is a horizontal line and horizontal lines are functions.

the second one is not a function because the coordinates cannot have different inputs but different outputs. each input must have only one output.

the coordinates for the second one are:

(2,5); (1,1); (1,2); (3,2)

and a function cannot have two same x-coordinates. it must pass the vertical line test which is a way to tell if something is a function or not. since the second graph does not pass the vertical line test, it is not a function

hope this helps :)

5 0

3 years ago

what is the surface area of a rectangular prisim with a base length of 9 yd, base width of 7 yd,and a height of 4 yd?

krek1111 [17]

Answer:

254 yds²

Step-by-step explanation:

There are 6 faces of the prism we need to calculate the area of for a rectangular prism.

The base and top of the prism measure 9x7 yards each, so there are two faces with an area of 63 yds² (9 x 7 = 63)

The sides of the prism measure 4x7 yards each, so there are two faces with an area of 28 yds² (4 x 7 = 28)

The front and back face of the prism measure 9x4 yards each, so there are two faces with an area of 36 yds² (9 x 4 = 36)

The total surface area is

2(63) + 2(28) + 2(36) = 254 yds²

3 0

3 years ago

Read 2 more answers

If f(x) = x^2 + 1 and g(x) = 3x + 1, find [f(4)]^2 81 257 289

Vedmedyk [2.9K]

So g(x) doesn't come in
ok

remember pemdas
inside first
evaluate f(4)
f(4)=4^2+1=16+1=17
now we have

[17]^2=289

answer s 289

7 0

3 years ago

Read 2 more answers

Calculate the number of subsets and the number of proper subsets for the set.

arlik [135]

A set of n elements has 2ⁿ subsets. One of these subsets is the set itself, so this set would have 2ⁿ - 1 proper subsets.

The given set has 4 elements, so it has 2⁴ = 16 subsets and 2⁴ - 1 = 15 proper subsets.

Just to illustrate the claim, we have

• subsets of size 0 (1 of these):

{ } (empty set)

• subsets of size 1 (4 of these):

{1/6}, {1/7}, {1/8}, {1/9}

• subsets of size 2 (6 of these):

{1/6, 1/7}, {1/6, 1/8}, {1/6, 1/9}, {1/7, 1/8}, {1/7, 1/9}, {1/8, 1/9}

• subsets of size 3 (4 of these):

{1/6, 1/7, 1/8}, {1/6, 1/7, 1/9}, {1/6, 1/8, 1/9}, {1/7, 1/8, 1/9}

• subsets of size 4 (1 of these):

{1/6, 1/7, 1/8, 1/9}

and the last one is the only subset that is not a proper subset, because that subset = the set.

6 0

2 years ago