Question

Is −8c an even integer? Yes, because −8c = 2(−4c) + 1 and −4c is an integer. Yes, because −8c = 2(−4c) and −4c is an integer. No, because −8c = 2(−4c) and −4c is an integer. No, because −8c = 2(−4c) + 1 and −4c is an integer.

Answer 1

Answer:

Yes, because −8c = 2(−4c) and −4c is an integer

Step-by-step explanation:

We want to determine whether $-8c$ is an even integer.

Recall that even integers are of the form: $2n$

Let us see if we can rewrite the given expression in the form 2n, where n is an integer.

Let us factor 2 to get:

$-8c=2(-4c)$

If -4c is an integer and we let m=-4c,then

$-8c=2(m)=2m$, where m is an integer.

Therefore the answer is Yes, because −8c = 2(−4c) and −4c is an integer