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djyliett [7]
3 years ago
11

In the first fifth of the season the Madgals played 12 games. If the Madgals won 60% of their games during the whole season, how

many games did they win?
Mathematics
2 answers:
Aleks [24]3 years ago
4 0

Answer:

the same thing he said. sorry

Step-by-step explanation:

Tema [17]3 years ago
3 0

Answer: Here is the answer and explanation because this is the fifth season and there are 12 games you multiply 5 by 12 and get 60 and 60 times 2/3 is 40 because you can spilt 60 into 3rds I third would be equal to 20 so 2/3 would be 40 ( please give brailiest and sorry if I didn’t explain it good. )

Step-by-step explanation:

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Help! Pls! I’ll mark you as top
inysia [295]
10 1/2x +2

- because you would add all the side lengths, so 2x+2x+ 3 1/4x+ 13 1/4x 1. You can combine like terms it to 10 1/2x+ 2.
7 0
3 years ago
I need help ASAP <br> Integrated math II
Molodets [167]

Answer:

\boxed{ \bold{ \sf{x = 16}}}

\boxed{ \bold{ \sf{m < AFD = 82}}}

Step-by-step explanation:

\sf{5x + 18 = 3x + 50}

( Being vertically opposite angles)

Vertically opposite angles are always equal.

Move variable to L.H.S and change it's sign

Similarly, Move constant to R.H.S and change it's sign

⇒\sf{5x  - 3x = 50 - 18}

Collect like terms

⇒\sf{2x = 50 - 18}

Subtract 18 from 50

⇒\sf{2x = 32}

Divide both sides of the equation by 2

⇒\sf{ \frac{2x}{2}  =  \frac{32}{2} }

Calculate

⇒\sf{x = 16}

The value of x is 16

Now, let's find value of m<AFD :

\sf{m < afd + 5x + 18 = 180} ( sum of angle in straight line )

plug the value of x

⇒\sf{m < AFD + 5 \times 16 + 18 = 180}

Multiply the numbers

⇒\sf{m < AFD + 80 + 18 = 180}

Add the numbers

⇒\sf{m < AFD + 98 = 180}

Move constant to R.H.S and change it's sign

⇒\sf{m < AFD = 180 - 98}

Subtract 98 from 180

⇒\sf{m < AFD = 82}

Value of m<AFD = 82

Hope I helped!

Best regards!!

3 0
3 years ago
Which of the following is a solution of x2 + 2x + 4?
ivolga24 [154]
Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:

</span>x^2 + 2x + 4= 0.  "Completing the square" seems to be the easiest way to go here:

rewrite   x^2 + 2x + 4  as   x^2 + 2x + 1^2 - 1^2 = -4, or
                                              (x+1)^2 = -3
or                                            x+1 =i*(plus or minus sqrt(3))

or                                            x = -1 plus or minus i*sqrt(3)

This problem, like any other quadratic equation, has two roots.  Note that the fourth possible answer constitutes one part of the two part solution found above.
3 0
3 years ago
the length of a rectangle is 6 meters less than twice the width. The area of the rectangle is 140m². Find the dimensions of the
AveGali [126]

Answer:

Here's what we know:

A = Lw (Area is length times width)

L = 2w + 6 (length is twice the width plus 6)

A = 140 (Area is 140 m2)

Plug in the variable values:

140 = w(2w + 6)

Distribute:

140 = 2w2 + 6w

Subtract 140:

2w2 + 6w - 140 = 0

Factor out a 2:

2(w2 + 3w - 70) = 0

Divide both sides by 2:

w2 + 3w - 70 = 0

(w + m)(w - n)

When we factor out the quadratic, we know it's going to be a +/- situation because the c value in the quadratic is negative, and the two numbers are going to be three away, the plus next to the 3 meaning that the larger number is going to be positive:

(w + 10)(w - 7) = 0

w = -10, 7

We can't have a negative length, so we can toss out the -10, leaving us with w = 7 meters.

L = 2 * 7 + 6

L = 14 + 6

L = 20

Check:

140 = 20 * 7

140 = 140

8 0
2 years ago
Read 2 more answers
Simplfy the expression 3x+4(x-6)-3(x-7)
Nikitich [7]

Answer:

the answer is 4x-3

Step-by-step explanation:

4 0
3 years ago
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