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djyliett [7]
3 years ago
11

In the first fifth of the season the Madgals played 12 games. If the Madgals won 60% of their games during the whole season, how

many games did they win?
Mathematics
2 answers:
Aleks [24]3 years ago
4 0

Answer:

the same thing he said. sorry

Step-by-step explanation:

Tema [17]3 years ago
3 0

Answer: Here is the answer and explanation because this is the fifth season and there are 12 games you multiply 5 by 12 and get 60 and 60 times 2/3 is 40 because you can spilt 60 into 3rds I third would be equal to 20 so 2/3 would be 40 ( please give brailiest and sorry if I didn’t explain it good. )

Step-by-step explanation:

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52.75 with a 25% discount. How much will he pay for it?
Allisa [31]

Answer:

He pays $39.56

Step-by-step explanation:

If finding the discount, always divide the percent by 100.

25% = 0.25

52.75*0.25=13.1875

Because its money, round to hundredths place, $13.19

Subtract the "percent" (13.19) from 52.75

52.75 - 13.19 = $39.56



7 0
3 years ago
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How many 3/5 are in 1/3
Alenkinab [10]

Answer:

4/15

Step-by-step explanation:

6 0
2 years ago
Answer please ill give brainlist and ten points
Dmitry_Shevchenko [17]

Answer:

The answer is 32.

Step-by-step explanation:

7 * A =

7 * 4 = 28

b^2 =

6^2 = 36

28 + 36 ÷ 9 = 32

So, the answer is 32.

Hope this helps! :)

3 0
3 years ago
16. If a customer's check subtotal comes to $27.14,
horsena [70]

Answer:

$28.77

Step-by-step explanation:

If the subtotal is $27.14, and the tax to add is 6%, the total would be:

$27.14*(1+0.06)=$28.77

3 0
3 years ago
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Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel
nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

\theta=\frac{\pi}{3}

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be=r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j

By using cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}

Force along the plane will be=\mid F_x\mid=F\cdot r

Force along the plane will be =\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3N

By using i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0

Therefore, force along the plane=\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)

2.The vector perpendicular to the plane=r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j

The force perpendicular to the plane=\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

The force perpendicular to the plane=4N

Therefore, F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=2\sqrt 3i-6j-2\sqrt3 i-2j=-8j

Hence,sum of two component of forces=Total force.

6 0
3 years ago
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