Step-by-step explanation:
In set a, every element in the domain has only 1 image in the range. This is called a one-to-one correspondence.
However in set b, there is a many-to-one correspondence as more than 1 element in the domain has the same image.
Step-by-step explanation:
1. A four-sided polygon is a/an
a. octagon
b. hexagon
c. <u>quadrilateral</u>
d. pentagon
e. heptagon,
2. a five-sided polygon is a/an
a. heptagon
b. quadrilateral
c. <u>pentagon</u>
d. octagon
e. hexagon
3. a six-sided polygon is a/an
a. pentagon
b. octagon,
c. heptagon
d. <u>hexagon</u>
e. quadrilateral
4. a seven-sided polygon is a/an
a. quadrilateral
b. pentagon
c. hexagon
d. octagon
e. <u>heptagon</u>
5. an eight-sided polygon is a/an
a. quadrilateral
b. pentagon
c. hexagon
d. <u>octagon</u>
e. heptagon
<u>Bold and underlined words are answers.</u>
Sure b and c would probs be right
|2x-3|=2x-1
need to consider two cases
(1) 2x-3<0 --> x<3/2
-(2x-3)=2x-1
x=1, and this is <3/2 so that's a valid solution
(2) 2x-3>=0 --> x>=3/2
2x-3=2x-1
-3 = -1 so there no solution for x>=3/2
The single solution is x=-1
