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Alecsey [184]
3 years ago
12

What is the solution to -2|2.2x - 3.3| = -6.6

Mathematics
2 answers:
lana66690 [7]3 years ago
7 0

Answer:

the answer would be x = 3, 0

Step-by-step explanation:

as much as I would like to, I'm really not that good at explaining things

Otrada [13]3 years ago
6 0

Answer:

that is the solution to the question

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I don't understand this question can you help me please
Maslowich
I believe the answer is A because the formula for area is length times width. 
5 0
3 years ago
Read 2 more answers
What is the volume of a cone with a radius of 4 centimeters and a height of 5 centimeters?
vovangra [49]

Answer:

83.79 cm²

Step-by-step explanation:

(please refer to attached)

recall that the volume of a cone is given by

V = (1/3) π r² h

where

r = radius = given as 4 cm

h = height = given as 5 cm

assume π = 3.142

substituting the values into the formula:

V = (1/3) π r² h

V = (1/3) (3.14) (4)² (5)

V = 83.79 cm²

8 0
3 years ago
PLEASE HELP THIS IS A LINEAR EQUATIONS AND INEQUALITIES!!!
Scrat [10]
I’m pretty sure this is the answer.
You don’t have all of the answer choices listed, sorry

7 0
3 years ago
What is the area of this figure?<br> Enter your answer in the box below.​
viva [34]

Answer:

A = 81 m²

Step-by-step explanation:

The formula for area of the parallelogram is

 A = LH         where L is the length of the base, and H is the height

L is given as 9, and H is given as 5, so

 A = (9)(5) = 45 m²

The are of the triangle is

 A = (1/2)bh         where b is the base and h is the height

b is given as 9.  Its's 9 because that side of the parallelogram is parallel to the base of the parallelogram and is also equal in measure.  The height of the triangle is give as 8, so the area is..

 A = (1/2)(9)(8)

       A = 36  m²

The total area is

45 m² + 36 m² = 81 m²

8 0
3 years ago
The X- and y-coordinates of point P are each to be chosen at random from the set of integers 1 through 10.
bagirrra123 [75]

Answer:

Ok, as i understand it:

for a point P = (x, y)

The values of x and y can be randomly chosen from the set {1, 2, ..., 10}

We want to find the probability that the point P lies on the second quadrant:

First, what type of points are located in the second quadrant?

We should have a value negative for x, and positive for y.

But in our set;  {1, 2, ..., 10}, we have only positive values.

So x can not be negative, this means that the point can never be on the second quadrant.

So the probability is 0.

3 0
2 years ago
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