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3 years ago

What is the solution to -2|2.2x - 3.3| = -6.6

Mathematics

2 answers:

lana66690 [7]3 years ago

7 0

Answer:

the answer would be x = 3, 0

Step-by-step explanation:

as much as I would like to, I'm really not that good at explaining things

Otrada [13]3 years ago

6 0

Answer:

that is the solution to the question

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Translate the sentence into an equation. Five more than the product of a number and 9 is equal to 6

kap26 [50]

The first thing we will do for this case is to define the following variable:
x = real number.
We then have the following sentence:
"Five more than the product of a number and 9 is equal to 6"
The equation sought is:
9x + 5 = 6
Answer:
An equation for the sentence is:
9x + 5 = 6

6 0

3 years ago

13. Distributive Property<br> 3(x - 1) = 3x - ?

goblinko [34]

Answer:

$\huge\boxed{3x-3}$

Step-by-step explanation:

$3(x-1)=\\\\\text{Distribute: }\left \{ {{3*x=3x} \atop {3*-1=-3}} \right.\\\\3(x-1)=\boxed{3x-3}$

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3 years ago

Read 2 more answers

Write 8 as a product of primes.<br> Use index notation

dimaraw [331]

Answer:

2³

Step-by-step explanation:

8 = 2 × 2 × 2 = 2³

4 0

2 years ago

Negitive 7 over 18 minus negitive 9 over 4 equals?

Inessa [10]

Answer:

1 31/36 is your answer

Step-by-step explanation:

Find common denominators. Note that what you do to the denominator, you must do to the numerator;

(-7/18)(2/2) = (-14/36)

(-9/4)(9/9) = (-81/36)

Combine the terms:

(-14/36) - (-81/36)

Note that two negative signs directly next to each other equals a positive sign.

(-14/36) + 81/36

-14/36 + 81/36

(-14 + 81)/36

Combine like terms. Solve the parenthesis:

(67)/36

Change to a mixed fraction:

(67/36) = 1 31/36

1 31/36 is your answer.

5 0

3 years ago

The sequence {an) is defined by ao = 1 and

otez555 [7]

<h3>Answer: 31</h3>

=======================================

Work Shown:

Use the value of a0 to find the value of a1. The idea is you double the previous value, and then add 1.

$a_{n+1} = 2*(a_n) + 1\\\\a_{0+1} = 2*(a_0) + 1\\\\a_{1} = 2*(1) + 1\\\\a_{1} = 3\\\\$

Which is then used to find the value of a2. Follow the same process as before (double the previous value and then add 1).

$a_{n+1} = 2*(a_n) + 1\\\\a_{1+1} = 2*(a_1) + 1\\\\a_{2} = 2*(3) + 1\\\\a_{2} = 7\\\\$

This is used to find a3

$a_{n+1} = 2*(a_n) + 1\\\\a_{2+1} = 2*(a_2) + 1\\\\a_{3} = 2*(7) + 1\\\\a_{3} = 15\\\\$

Finally we can now find a4

$a_{n+1} = 2*(a_n) + 1\\\\a_{3+1} = 2*(a_3) + 1\\\\a_{4} = 2*(15) + 1\\\\a_{4} = 31\\\\$

Recursive sequences like this aren't too bad if n is small, but as n gets larger, things become more tedious. For those cases, its best to try to find a closed form equation. If not, then the next best thing is using a spreadsheet to automate the process.

6 0

3 years ago