The answer is A, 1. In the statement x^2 >x, if we try 4, 5 and 8 for x, we get 16, 25 and 64 for x^2. The statement is true. But if we try x = 1, when we square it we still have 1. Therefore for x=1, x^2>x is false.
<span>4k – 6 = -2k – 16 – 2
</span>4k+2k = – 16 – 2+6
6k=-12
k=-2
Hope this helps
Answer:
9 and 1/2
Step-by-step explanation:
The solution is y = -5
What is Quadratic Equation?
A quadratic equation is a second-order polynomial equation in a single variable x , ax² + bx + c = 0. with a ≠ 0. Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has at least one solution. The solution may be real or complex.
Given data ,
Let the function be f ( x ) = y
And , y = x² + 2x - 8
So , f ( x ) = x² + 2x - 8
Substituting the value for x in the equation , we get
When x = -3
f ( -3 ) = ( -3 )² + 2( -3 ) - 8
= 9 - 6 - 8
= 9 - 14
f ( -3 ) = -5
When x = 1
f ( 1 ) = ( 1 )² + 2( 1 ) - 8
= 1 + 2 - 8
= 3 - 8
f ( 1 ) = -5
Hence , the value of y = -5
To learn more about quadratic equation click :
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4(2x+1) = 3(x+8)
8x + 4 = 3x + 24
5x = 20
∴x = 4
