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Goryan [66]
4 years ago
9

A square is dilated by a scale factor of 4/5 to create a new square. What is the relationship between the new area and the origi

nal area?
A. The area of the new rectangle is 16/5 the original area.
B. The area of the new rectangle is 64/125 the original area.
C. The area of the new rectangle is 4/5 the original area.
D. The area of the new rectangle is 16/25 the original area.
Mathematics
1 answer:
alex41 [277]4 years ago
3 0

Answer: C. The area of the new rectangle is 4/5 the original area.

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What is the sum of the square root of 100<br> a 1000<br> b 100<br> c 10,000<br> d 10
Natasha2012 [34]

Answer: D The square root of 100 is 10. Or,

√100 = 10

Step-by-step explanation:

5 0
3 years ago
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2 Points
mario62 [17]

Answer:

B and E

Step-by-step explanation:

Given the rational expression

\frac{x-7}{2x^2-32} ← factorise the denominator

2x² - 32 ← take out a common factor of 2 from each term

= 2(x² - 16) ← (x² - 16) is a difference of squares

= 2(x - 4)(x + 4)

The expression can now be written as

\frac{x-7}{2(x-4)(x+4)}

The denominator of the expression cannot be zero as this would make the expression undefined. Equating the denominator to zero and solving gives the values that x cannot be.

2(x - 4)(x + 4) = 0

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x + 4 = 0 ⇒ x = - 4

These are the values of x that make the expression undefined.

x = 4 → B

x = - 4 → E

4 0
3 years ago
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Which ordered pair is a solution to the system of equations y=x+3 and y=x^2-x
Elenna [48]

For this case we have the following system of equations:

y = x + 3\\y = x ^ 2-x

Equating the equations we have:

x ^ 2-x = x + 3\\x ^ 2-x-x-3 = 0\\x ^ 2-2x-3 = 0

To find the solutions we factor the equation. To do this, we look for two numbers that, when multiplied, result in -3 and when added, result in -2.

These numbers are: -3 and +1

-3 + 1 = -2\\-3 * (+ 1) = - 3

Thus, the factored equation is:

(x-3) (x + 1) = 0

Then, the solutions for the variable "x" are:

x_ {1} = 3\\x_ {2} = - 1

We find the solutions for the variable "y":

y_ {1} = x_ {1} + 3 = 3 + 3 = 6\\y_ {2} = x_ {2} + 3 = -1 + 3 = 2

Thus, the solutions are:

(x_ {1}, y_ {1}): (3,6)\\(x_ {2}, y_ {2}): (-1,2)

ANswer:

(x_ {1}, y_ {1}): (3,6)\\(x_ {2}, y_ {2}): (-1,2)

3 0
4 years ago
Please answer #3 only
DedPeter [7]

Answer:

4.75 x 300 is 1,425

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Which of the following values are not in the range of the function f(x)=x2?
MrMuchimi

Answer:

B) -3

Step-by-step explanation:

Prepworks!! :D

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3 years ago
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