Answer:
what is due for now... share us the image?
Solutions
We know that a ticket costs £14.50 and it is increased by <span>7% in price. To solve the problem lets use variables.
Let the Variable Y</span><span> = 7% of 14.5
Equation: Y = P% </span>×<span> (X)
Solve for our equation Y
Y = P% </span>×<span> (X)
Y = 7% </span>×<span> 14.5
Now lets convert the percent to a decimal:
Percent = Out of 100
Percent = 7% / 100 = 0.07
Y = 0.07 </span>×<span> 14.5
Y = 1.015
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Answer:
The center of the circle is at;
![(1,-3)](https://tex.z-dn.net/?f=%281%2C-3%29)
The radius of the circle is;
![r=4](https://tex.z-dn.net/?f=r%3D4)
Explanation:
Given the equation of circle;
![x^2+y^2-2x+6y-6=0](https://tex.z-dn.net/?f=x%5E2%2By%5E2-2x%2B6y-6%3D0)
we want to re-write it in the form;
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
where;
![\begin{gathered} (h,k)\text{ is the center of the circle} \\ r\text{ is the radius} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%28h%2Ck%29%5Ctext%7B%20is%20the%20center%20of%20the%20circle%7D%20%5C%5C%20r%5Ctext%7B%20is%20the%20radius%7D%20%5Cend%7Bgathered%7D)
Applying Completing the square method;
![\begin{gathered} x^2+y^2-2x+6y-6=0 \\ x^2-2x+1+y^2+6y+9=6+1+9 \\ (x-1)^2+(y+3)^2=16 \\ (x-1)^2+(y+3)^2=4^2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E2%2By%5E2-2x%2B6y-6%3D0%20%5C%5C%20x%5E2-2x%2B1%2By%5E2%2B6y%2B9%3D6%2B1%2B9%20%5C%5C%20%28x-1%29%5E2%2B%28y%2B3%29%5E2%3D16%20%5C%5C%20%28x-1%29%5E2%2B%28y%2B3%29%5E2%3D4%5E2%20%5Cend%7Bgathered%7D)
comparing the derived equation to the general form we have;
![\begin{gathered} h=1 \\ k=-3 \\ r=4 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%3D1%20%5C%5C%20k%3D-3%20%5C%5C%20r%3D4%20%5Cend%7Bgathered%7D)
Therefore;
The center of the circle is at;
![(1,-3)](https://tex.z-dn.net/?f=%281%2C-3%29)
The radius of the circle is;