we have the lines
x-3=6
x=6+3
x=9
this is a vertical line (parallel to the y-axis)
The slope is undefined
and
y=3x+4
The slope is m=3
Compare their slopes
1) Their slopes are not equal -----> are not parallel lines
2) Their slopes are not negative reciprocal -----> are not perpendicular lines
therefore
<h2>The answer is neither</h2>
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
To learn more about the solution visit:
brainly.com/question/1397278
Answer:
a. or 
Step-by-step explanation:
Slope is equal to y1-y2 over x1-x2.
So the equation would be:
2-(-1)=2+1=3
-3-(-1)=-3+1=-2
So the answer is:
The quick and easy answer is 3/100
