Part A.
The set of equations can be solved by substitution. Use the expression one equation gives for y as the value of y in the other equation. This gives
2x²-15 = 3x-6
Subtracting the right side gives a quadratic in standard form that can be solved by any of several methods.
2x² -3x -9 = 0
(2x+3)(x-3) = 0 . . . . factor the above equation
x = -3/2, x = 3 . . . . .use the zero product rule to find x
Now, these x-values can be substituted into either equation for y. The linear equation is often easier to evaluate.
y = 3(-3/2) -6 = -10.5
y = 3(3)-6 = 3
The solutions to the system are (-1.5, -10.5) and (3, 3).
Part B.
The two equations can be graphed. The solutions are where the graphs intersect. The graphs intersect where the (x, y) values that satisfy one equation are the same (x, y) values that satisfy the other equation. Those points of intersection are (-1.5, -10.5) and (3, 3).
Answer:
First, 32 rounded to the nearest ten is:
30
Step-by-step explanation:
When rounding to the nearest ten, like we did with 32 above, we use the following rules:
A) We round the number up to the nearest ten if the last digit in the number is 5, 6, 7, 8, or 9.
B) We round the number down to the nearest ten if the last digit in the number is 1, 2, 3, or 4.
C) If the last digit is 0, then we do not have to do any rounding, because it is already to the ten.
The quadratic formula is (-b+-sqrt(b^2-4ac))/(2a)
In your equation,
A=2
B=-10
C=7
Plugging these in we get
(10+-sqrt(100-4(2)(7)))/(2*2)
=(10+-sqrt(44))/4
=(10+-6.633)/4
=16.633/4 or -3.366/4
=4.158 or -0.841
Final Answer:
x=4.158 or x=-0.841
Hope I helped :)
Answer:
$891.3
Step-by-step explanation:
686 x 1.3 = 891.3
Consider ∆JWZ and ∆JKZ
WZ~KJ (given)
<u>/</u><u> </u><u>WZJ</u>~<u>/</u><u> </u>KJZ (given)
JZ~JZ (common)
Therefore,
∆JWZ~∆JKZ by SAS congruence rule.
JW~ZK by CPCT.