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3 years ago

How many possible outcomes are there if you choose a card from a standard deck?

Mathematics

1 answer:

MaRussiya [10]3 years ago

7 0

Total outcomes: 52- 1% chance of any card

Outcomes for each type of card(heart, diamond,spades,cloves): 4 -25%

hope this helps

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What all numbers whose absolute value is 6

GalinKa [24]

Answer:

6, -6

Explanation:

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3 0

2 years ago

Lauren wants to save 30% of her weekly paycheck. How much will she save each week if her paycheck is $150 a week?

Vlad1618 [11]

She will save $45 dollars a week the working is
150÷10
=15
30%=15×3
$45

3 0

2 years ago

One-fourth of a number is five-eights. Find the number. Simplify your answer

NNADVOKAT [17]

Answer:

2.50 or 2.5

Step-by-step explanation:

1/4=.25 so 25% of a number=5/8=0.625

So we multiply .625*4 to get the number. Since it's 25% and we want 100% to get it back to the original number

.625*4=2.50 or 2.5

5 0

2 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago

Is the relation a function? {(-1,7), (9,4), (3,-2), (5,3), (9,1)}

guapka [62]

Answer:

Yes. it is a function

Step-by-step explanation:

None of the x's axis are the same

7 0

2 years ago