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3241004551 [841]
3 years ago
5

In the last quarter of​ 2007, a group of 64 mutual funds had a mean return of 4.8​% with a standard deviation of 5.8​%. If a nor

mal model can be used to model​ them, what percent of the funds would you expect to be in each​ region? Use the​ 68-95-99.7 rule to approximate the probabilities rather than using technology to find the values more precisely. Be sure to draw a picture first. ​a) Returns of 10.6​% or more ​b) Returns of 4.8​% or less ​c) Returns between negative 12.6​% and 22.2​% ​d) Returns of more than 16.4​%
Mathematics
1 answer:
saw5 [17]3 years ago
4 0

Answer:

a) 16%; b) 50%; c) 99.7%; d) 2.5%

Step-by-step explanation:

In a normal curve, the empirical rule states that 68% of data falls within 1 standard deviation of the mean.  This means for this problem, 68/2 = 34% of data falls from

4.8-5.8 = -1 to 4.8, and 34% falls from 4.8 to

4.8+5.8 = 10.6.

95% of data falls within 2 standard deviations of the mean.  This includes the 68%; this means this leaves 95-68 = 27/2 = 13.5% to fall from

-1-5.8 = -6.8 to -1, and 13.5% falls from 10.6 to

10.6+5.8 = 16.4.

99.7% of data falls within 3 standard deviations of the mean.  This includes the 95%; this means this leaves 99.7-95 = 4.7/2 = 2.35% to fall from

-6.8-5.8 = -12.6 to -6.8, and 2.35% falls from 16.4 to

16.4+5.8 = 22.2.

This leaves 100-99.7 = 0.3/2 = 0.15% to fall from the left end to -12.6, and 0.15% to fall from 22.2 to the right end.

For part a,

For returns of 10.6 or more, we would add everything above this value:

13.5+2.35+0.15 = 16%.

For part b,

Since 4.8 is the mean, 50% of data falls below this.

For part c,

-12.6 is 3 standard deviations from the mean, and 22.2 is 3 standard deviations from the mean.  This means that 99.7% of the data falls between these values.

For part d,

We add together all values above 16.4:  2.35+0.15 = 2.5%

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Answer: 475.2

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The area of the right triangle with long leg 12, short leg x,

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The area of the little right triangle is

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Answer:

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Step-by-step explanation:

We are given that From previous polls, it is believed that 66% of likely voters prefer the incumbent.

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Let p = probability of voters preferring the incumbent = 66%

n = number of voters polled = 500

<u>So, the mean of the number preferring the incumbent is given by;</u>

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<u>And, standard deviation of the number preferring the incumbent is given by;</u>

          Variance =  n \times p\times (1-p)  

                          =  500 \times 0.66 \times (1-0.66)

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So, Standard deviation =  \sqrt{Variance}

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steps below

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