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3 years ago

Brian bought a fish tank that is 22 in. long, 12 in. wide, and 16 in. tall. Which is the volume of the fish tank?

Mathematics

2 answers:

weeeeeb [17]3 years ago

5 0

Answer: 4224 feet cubed

Step-by-step explanation:

Volume for a rectangular tank =LxWxH

22x12x16=4,224

MaRussiya [10]3 years ago

5 0

Answer:

4224in^3

Step-by-step explanation:

The formula for volume is height x length x width ( x means multiply)

so to find the volume of the fish tank you multiply each of the sides by each other, 12x16x22. So the volume of the fishtank is 4224 inches cubed(^3) make sure you write the cubed and units at the end, just like how for area you always make it squared.

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Answer:

$-3a^2 - 5a + 4$

Step-by-step explanation:

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3 years ago

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If a person is not a banjo player , then the person is not a musician

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3 years ago

How To work this out ?

MrMuchimi

(a) Using the completing the square method, we need to write into the form of where , so
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3 years ago

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Sliva [168]

Answer:

Step-by-step explanation:

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3 years ago

We considered the differences between the temperature readings in January 1 of 1968 and 2008 at 51 locations in the continental

mr Goodwill [35]

Answer:

$1.1-2.02\frac{4.9}{\sqrt{50}}=-0.30$

$1.1+2.02\frac{4.9}{\sqrt{50}}=2.50$

So on this case the 90% confidence interval would be given by (-0.30;2.50)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=1.1$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=4.9 represent the sample standard deviation

n=51 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=51-1=50$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,50)".And we see that $t_{\alpha/2}=2.02$

Now we have everything in order to replace into formula (1):

$1.1-2.02\frac{4.9}{\sqrt{50}}=-0.30$

$1.1+2.02\frac{4.9}{\sqrt{50}}=2.50$

So on this case the 90% confidence interval would be given by (-0.30;2.50)

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3 years ago