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aev [14]
3 years ago
12

First Data Corp. records indicate that in 2005, 43% of adult email users received a phishing email. A phishing email replicates

an authentic site for the purpose of stealing personal information such as account numbers and passwords. Suppose a random sample of 800 adults will be surveyed on whether they have received phishing emails to determine recent trends. Give the mean of the sample distribution of LaTeX: \hat{p}p ^. Give your answers in decimal form and round to two decimal places. (Example: 0.39)
Mathematics
2 answers:
lbvjy [14]3 years ago
6 0

Answer:

The answer is 0.43

Step-by-step explanation:

Given:

43 percentage (43%) of the adult users received a phishing e - mail

Total numbers of adult selected at random for phishing e - mail  = 800

Solution

Let Y represent Total numbers of adults sampled at random

Let X represent the number of adults that received

:. X = 43% of Y

43% of 800

=  \frac{43}{100} x 800  = 344.

mean = \frac{x}{800} = \frac{344}{800}

mean of the sample distribution  = 0.43

ra1l [238]3 years ago
5 0

Answer:

P(x) = 45/100 = 0.45

Mean sample distribution = probability x number sampled by the survey.

Mean sample distribution = 0.45 x 800 = 360.00 to two decimal places.

Step-by-step explanation:

Convert the percentage to decimal probability.

45%. P(x) = 45/100 = 0.45

If there are ranges of probability values, we construct a probability distribution table. This is not necessary in the case of one probability value(45%)

Multiply the probability by the number adults to be surveyed on whether they have received phishing emails.

0.45 x 800 = 360.

Here, we assume that the 45% recorded by 2005 data, is still valid for the recent trends.

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