Question

First Data Corp. records indicate that in 2005, 43% of adult email users received a phishing email. A phishing email replicates an authentic site for the purpose of stealing personal information such as account numbers and passwords. Suppose a random sample of 800 adults will be surveyed on whether they have received phishing emails to determine recent trends. Give the mean of the sample distribution of LaTeX: \hat{p}p ^. Give your answers in decimal form and round to two decimal places. (Example: 0.39)

Answer 1

Answer:

The answer is 0.43

Step-by-step explanation:

Given:

43 percentage (43%) of the adult users received a phishing e - mail

Total numbers of adult selected at random for phishing e - mail  = 800

Solution

Let Y represent Total numbers of adults sampled at random

Let X represent the number of adults that received

:. X = 43% of Y

43% of 800

=  $\frac{43}{100}$ x 800  = 344.

mean = $\frac{x}{800}$ = $\frac{344}{800}$

mean of the sample distribution  = 0.43

Answer 2

Answer:

P(x) = 45/100 = 0.45

Mean sample distribution = probability x number sampled by the survey.

Mean sample distribution = 0.45 x 800 = 360.00 to two decimal places.

Step-by-step explanation:

Convert the percentage to decimal probability.

45%. P(x) = 45/100 = 0.45

If there are ranges of probability values, we construct a probability distribution table. This is not necessary in the case of one probability value(45%)

Multiply the probability by the number adults to be surveyed on whether they have received phishing emails.

0.45 x 800 = 360.

Here, we assume that the 45% recorded by 2005 data, is still valid for the recent trends.