Answer:
8/6 > 7/9
Step-by-step explanation:
i got u snow miku
Answer:
D (9,3)
Step-by-step explanation:
just did the quiz/test.
<h2>
Explanation:</h2><h2>
</h2>
Here we have the following expression:

What we need to do is to substitute
into our expression. Therefore:

Finally, when evaluating
into the expression the result is 4.
Answer:
(-4,-7)
(4,7)
(-4,-5)
(1,-1)
Step-by-step explanation:
<u>Answer:</u>
Factor over complex numbers of
is 
<u>Solution: </u>
From question given that
→ (1)
On substituting
in equation (1),

Taking 2 as a common in above expression,

Rewrite the above expression,
![=2\left[y^{2}+2(y)(9)+9^{2}\right]](https://tex.z-dn.net/?f=%3D2%5Cleft%5By%5E%7B2%7D%2B2%28y%29%289%29%2B9%5E%7B2%7D%5Cright%5D)
![\left[\text { Using }(a+b)^{2}=a^{2}+2 a b+b^{2}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Ctext%20%7B%20Using%20%7D%28a%2Bb%29%5E%7B2%7D%3Da%5E%7B2%7D%2B2%20a%20b%2Bb%5E%7B2%7D%5Cright%5D)
![\left[\text { since } y=x^{2}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Ctext%20%7B%20since%20%7D%20y%3Dx%5E%7B2%7D%5Cright%5D)
![\left[\text { Using } a^{2}+b^{2}=(a+i b)(a-i b), \text { where } i=\sqrt{-1}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Ctext%20%7B%20Using%20%7D%20a%5E%7B2%7D%2Bb%5E%7B2%7D%3D%28a%2Bi%20b%29%28a-i%20b%29%2C%20%5Ctext%20%7B%20where%20%7D%20i%3D%5Csqrt%7B-1%7D%5Cright%5D)
![=2[(x+3 i)(x-3 i)]^{2}](https://tex.z-dn.net/?f=%3D2%5B%28x%2B3%20i%29%28x-3%20i%29%5D%5E%7B2%7D)

Hence Factor over complex numbers of
is 