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Reika [66]
3 years ago
14

How do you write 8.825 in words?

Mathematics
2 answers:
Ivan3 years ago
8 0
Eight point eight twenty-five
aksik [14]3 years ago
4 0
Eight with the decimal numbers of eight hundred twenty-five.
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I actually did this problem today for edge , I included a picture that I used to understand how to do this problem the answer is 1%.

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Two lengths of a triangle are shown.
valina [46]

Answer:

9 in.?

Step-by-step explanation:

pythagoras theorem

if jl is the hypotenuse you do the square root of 10² - 5²

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Find the length of the altitude drawn to the hypotenuse.the triangle is not drawn to scale
Marrrta [24]

Answer:

4√5

Step-by-step explanation:

Let's call it x

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6 0
3 years ago
Use the strategy to simplify 4\sqrt(576)<br> Write the prime factorization of the radicand.
Ronch [10]
<h3>Answer:   96</h3>

===================================================

Work Shown:

4\sqrt{576}\\\\4\sqrt{2*2*2*2*2*2*3*3}\\\\4\sqrt{(2*2)*(2*2)*(2*2)*(3*3)}\\\\4\sqrt{(2)^2*(2)^2*(2)^2*(3)^2}\\\\4\sqrt{(2*2*2*3)^2}\\\\4\sqrt{24^2}\\\\4*24\\\\96\\\\

6 0
3 years ago
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If you roll two six-faced dice together, you will get 36 possible outcomes. 4 pts 1. List all possible outcomes of the experimen
bezimeni [28]

Given:

Two dice are rolled together.

Total number of possible outcomes.

To find:

The list of total possible outcomes.

The probability of getting a sum of 11 in these outcomes.

The probability of getting a sum less than or equal to 4.

The probability of getting a sum of 13 or more.

Solution:

If two dice are rolled together, then the total number of possible outcomes is 36 and list of total possible outcomes is

S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Sum of 11 in these outcomes = {(5,6),(6,5),(6,6)} = 3

The probability of getting a sum of 11 in these outcomes is

P(\text{sum=11})=\dfrac{3}{36}

P(\text{sum=11})=\dfrac{1}{12}

Therefore, the probability of getting a sum of 11 in these outcomes is \dfrac{1}{12}.

Sum less than or equal to 4 = {(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)} = 6

The probability of getting a sum less than or equal to 4 is

P({sum\leq 4})=\dfrac{6}{36}

P({sum\leq 4})=\dfrac{1}{6}

Therefore, the probability of getting a sum less than or equal to 4 is \dfrac{1}{6}.

Sum of 13 or more = empty set because maximum sum is 12.

The probability of getting a sum of 13 or more is

P(sum\geq 13)=\dfrac{0}{36}

P({sum\geq 13})=0

Therefore, the probability of getting a sum of 13 or more is 0.

8 0
3 years ago
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