x= -0.25 and 1.25
x = -0.5 and 1.5
x = 0 and 1
x = -0.375 and 1.625
Step-by-step explanation:
Given equation of the curve is
(i)
First equation 
Here y = 0
In x-axis the value of y = 0
The graph cuts the x-axis at(-0.25,0) and (1.25,0)
So, x= -0.25 and 1.25
(ii)
here y = 2
The line y= 2 cuts the curve at (-0.5,2) and (1.5,2)
So, x = -0.5 and 1.5
Given equation of the curve is
(i)
Here y = -1
The line y = -1 cuts the curve at (0,-1) and (1,-1)
So x = 0 and 1
(ii)
Here y = x+1
The line y -x =1 cuts the curve at (-0.375,0.5) and (1.625,2).
So x = -0.375 and 1.625
Answer:
what? I don't understand explain
The general form of a solution of the differential equation is already provided for us:
where 
. We now want to find a solution 
such that 
and 
. Therefore, all we need to do is find the constants 
and 
that satisfy the initial conditions. For the first condition, we have:
For the second condition, we need to find the derivative 
first. In this case, we have:
Therefore:
This means that we must solve the following system of equations:
If we add the equations above, we get:
If we now substitute 
into either of the equations in the system, we get:
This means that the solution obeying the initial conditions is:
Indeed, we can see that:
which do correspond to the desired initial conditions.
Answer:
7
Step-by-step explanation:
means x*x = 49
x * x = 49
x= 7
Hope this helps :)
Have a great day!
Option C
<u>SOLUTION:</u>
We need to find the value of B - CF
First find the value CF:
![CF=\left[\begin{array}{ccc}12&0&1.5\\1&-6&7\\\end{array}\right] \left[\begin{array}{ccc}-2&0\\0&8\\2&1\end{array}\right]](https://tex.z-dn.net/?f=CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%260%261.5%5C%5C1%26-6%267%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%260%5C%5C0%268%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D)
![CF=\left[\begin{array}{ccc}12(-2)+0 *0+1.5*2&12*0+0.8+1.5*1\\1*(-2)+(-6)*0+7.2&1*0+(-6)*8+7.1\\\end{array}\right]](https://tex.z-dn.net/?f=CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%28-2%29%2B0%20%2A0%2B1.5%2A2%2612%2A0%2B0.8%2B1.5%2A1%5C%5C1%2A%28-2%29%2B%28-6%29%2A0%2B7.2%261%2A0%2B%28-6%29%2A8%2B7.1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![CF=\left[\begin{array}{ccc}-21&1.5\\12&-41\\\end{array}\right]](https://tex.z-dn.net/?f=CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-21%261.5%5C%5C12%26-41%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Now find value of B - CF:
![B-CF=\left[\begin{array}{ccc}2&8\\6&3\\\end{array}\right] -\left[\begin{array}{ccc}-21&1.5\\12&-41\\\end{array}\right]](https://tex.z-dn.net/?f=B-CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%268%5C%5C6%263%5C%5C%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-21%261.5%5C%5C12%26-41%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![B-CF=\left[\begin{array}{ccc}23&6.5\\-6&44\\\end{array}\right]](https://tex.z-dn.net/?f=B-CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D23%266.5%5C%5C-6%2644%5C%5C%5Cend%7Barray%7D%5Cright%5D)
∴ the value of B - CF is ![\left[\begin{array}{ccc}23&6.5\\-6&44\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D23%266.5%5C%5C-6%2644%5C%5C%5Cend%7Barray%7D%5Cright%5D)
<em>I hope this helps....</em>
