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Westkost [7]
3 years ago
5

4. Lisa walked 48 blocks in 3 hours. blocks per hour

Mathematics
1 answer:
dlinn [17]3 years ago
3 0

Answer:

The number of blocks in one hour is the same that the unit rate, so 16 blocks per hour

Step-by-step explanation:

we know that

To find out the unit rate, divide the total blocks by the total time

so

\frac{48}{3}\ \frac{blocks}{hours}=16\ \frac{blocks}{hour}

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ANSWER A IF ON PLATO

Step-by-step explanation:

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4 0
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If b=33.2 and B=61(Degrees), find a on a right triangle.
Andru [333]
The degree of A would be 85.8 because it has to add up to 180
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Hokiris ladder has two legs that are each 8 feet long. When the ladder is opened safely and locked for use, the legs are 4 feet
guajiro [1.7K]

To solve this problem you must apply the proccedure shown below:

1- The ladder forms an isosceles triangle, because it has two equal sides.

2- Let's call the angle \alpha. To calculate it , you can divide the triangle into two equal right triangles and the angle \alpha will be divided into two equal parts too. Therefore, you can calculate the half of the angle and then multiply it by two, as following:

Sin^{-1}(\alpha 1)=opposite/hypotenuse

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6 0
3 years ago
Cellus
Paladinen [302]

Answer:

9/4

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x^2-3x-1=0

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Hope that helps!

4 0
3 years ago
Question
Jobisdone [24]

Answer:

The light bulb will reach the ground 1.25 seconds after it is dropped.

Step-by-step explanation:

We know that for an object that is in the air, the only force acting on it will be the gravitational force (where we are ignoring the air resistance)

Then the acceleration of the object is the gravitational acceleration, 32.17 ft/s^2

Then the acceleration of the light bulb is:

A(t) = (-32.17 ft/s^2)

Where the negative sign is because the acceleration is downwards.

Now, to get the velocity equation, we need to integrate the acceleration over time, we will get:

V(t) = (-32.17 ft/s^2)*t + V0

Where V0 is the initial velocity of the light bulb. Because it is dropped, the initial velocity will be zero, then V0 = 0m/s, then the velocity equation is:

V(t) =  (-32.17 ft/s^2)*t

Finally, to get the position equation we need to integrate again, we will get:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + P0

Where P0 is the initial height of the object, and in this case, we know that it is equal to 25 ft.

Then the position equation is:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + 25ft

The object will hit the ground when P(t) = 0 ft, then we need to solve that equation for t:

P(t) =  (1/2)*(-32.17 ft/s^2)*t^2 + 25ft = 0 ft

          25 ft =  (1/2)*(32.17 ft/s^2)*t^2

         2*25ft = (32.17 ft/s^2)*t^2

           50ft =  (32.17 ft/s^2)*t^2

         √( 50ft/(32.17 ft/s^2)) = t = 1.25 s

The light bulb will reach the ground 1.25 seconds after it is dropped.

8 0
3 years ago
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