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gulaghasi [49]
3 years ago
14

What is 2+2 and 69+50

Mathematics
2 answers:
Alik [6]3 years ago
7 0
4 and 119

dadadadadadadadadadadadada
ycow [4]3 years ago
3 0
2+2= 4 and 69+50=119
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A locker requires a three-digit code to open the lock. The code must contain one letter and two numbers, and no letter or number
mixas84 [53]

A locker requires a three-digit code to open the lock. The code must contain one letter and two numbers, and no letter or number can be repeated. You can choose from among four letters, A, B, C, and D, and two numbers, 5 and 6.

The size of the sample space is: (8, 16, 20, 24)

If a code is chosen at random, the probability that it has a letter that immediately follows an odd number is: (1/8, 1/6, 1/3, 2/5, 2/3)

If a code is chosen at random, the probability that D is in the code but is not in the first position is: (1/8, 1/6, 1/3, 2/5, 2/3)

5 0
3 years ago
Read 2 more answers
Suppose that a cyclist began a 476
mojhsa [17]
Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus    \bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{eastbound cyclist}&d&r&8.5\\
\textit{westbound car}&476-d&r+33.2&8.5
\end{array}\\\\
-----------------------------\\\\
\begin{cases}
\boxed{d}=8.5r\\\\
476-d=(r+33.2)8.5\\
----------\\
476-\boxed{8.5r}=(r+33.2)8.5
\end{cases}

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2
6 0
3 years ago
You have been saving nickels, dimes, and quarters in a jar for about a year. You decide to see how much money you've saved up. W
anyanavicka [17]

Answer:

x = number of nickels = 127

y = number of dimes = 156

z = number of quarters = 78

Step-by-step explanation:

Let

x = number of nickels

y = number of dimes

z = number of quarters

Total worth of the coins = $41.45

Total number of coins = 361

x + y + z = 361 (1)

dime = $0.1,

nickel = $0.05

quarter = $0.25

0.05x + 0.1y + 0.25z = 41.45 (2)

twice as many dimes as quarters.

y = 2z

Substitute y = 2z into (1) and (2)

x + 2z + z = 361

0.05x + 0.1(2z) + 0.25z = 41.45

x + 3z = 361

0.05x + 0.2z + 0.25z = 41.45

x + 3z = 361 (3)

0.05x + 0.45z = 41.45 (4)

Multiply (4) by 20

x + 3z = 361 (3)

x + 9z = 829 (5)

Subtract (3) from (5)

9z - 3z = 829 - 361

6z = 468

Divide both sides by 6

z = 468 / 6

= 78

z= 78

Recall,

y = 2z

= 2(78)

= 156

y = 156

Substitute the value of y and z into

x + y + z = 361

x + 156 + 78 = 361

x + 234 = 361

x = 361 - 234

= 127

x= 127

x = number of nickels = 127

y = number of dimes = 156

z = number of quarters = 78

6 0
3 years ago
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10q equals 7p because of the difference
4 0
4 years ago
True or False. If False explain your reason
faust18 [17]
1. false because it has only 2 triangular faces
2. true
3. true
4. i think its false, it has four
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