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vesna_86 [32]
3 years ago
5

On the number line, which month`s temperature will be between April and May?

Mathematics
1 answer:
Over [174]3 years ago
4 0
On the number line, April is represented by the number 15.
On the number line, May is represented by the number 20.

So, we have to find the month that is represented by a number that is between 15 and 20.

March is represented by the number 16, and is between 15 and 20.

So, on the number line, MARCH'S TEMPERATURE will be between April and May.

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I need help with this question (Trigonometry)
Solnce55 [7]
A)2.8
b1) 4.5/2.8
b2)impossible because if you want to do trigonometry you can't have that is an angle (Which is 148.1) larger than 90 degrees.
but if its angle BAF then the angle would be 2.8/5.3
c)41.32
8 0
3 years ago
1. for what constant k must f(k) always equal the constant term of f(x) for any polynomial f(x) 2. If we multiply a polynomial b
DIA [1.3K]

Answer:

1. k=0

2. yes, result is still a polynomial.

3. yes, f and g must have the same degree to have deg(f+g) < deg(f) or deg(g)

Step-by-step explanation:

1. for what constant k must f(k) always equal the constant term of f(x) for any polynomial f(x)

for k=0 any polynomial f(x) will reduce f(k) to the constant term.

2. If we multiply a polynomial by a constant, is the result a polynomial?

Yes, If we multiply a polynomial by a constant, the result is always a polynomial.

3. if deg(f+g) is less than both deg f and deg g, then must f and g have the same degree?

Yes.  

If

deg(f+g) < deg(f) and

deg(f+g) < deg(g)

then it means that the two leading terms cancel out, which can happen only if f and g have the same degree.

5 0
3 years ago
3(x + 3) + 10
Sphinxa [80]

Answer:

b-3x+19

Step-by-step explanation:

you have to open the bracket so 3*x=3x

3*3=9

therefore;3x+9+10=3x+19

7 0
3 years ago
Read 2 more answers
How many miles would Tegan bike 16 hours?
lions [1.4K]
252 is the answer hope it helps
3 0
3 years ago
Read 2 more answers
Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 56°, a = 12, b = 14
Eva8 [605]
We know that
case 1)
Applying the law of sines
a/Sin A=b/Sin B
A=56°
a=12
b=14
so
a*Sin B=b*Sin A----> Sin B=b*Sin A/a---> Sin B=14*Sin 56°/12
Sin B=0.9672
B=arc sin (0.9672)------> B=75.29°-----> B=75.3°

find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+75.3)----> C=48.7°

find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 48.7°/Sin 56°)
c=10.87-----> c=10.9

the answer Part 1)
the dimensions of the triangle N 1
are
a=12  A=56°
b=14  B=75.3°
c=10.9  C=48.7°

case 2) 
A=56°
a=12
b=14
B=180-75.3----> B=104.7°

find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+104.7)----> C=19.3°

find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 19.3°/Sin 56°)
c=4.78-----> c=4.8

the answer Part 2)
the dimensions of the triangle N 2
are
a=12  A=56°
b=14  B=104.7°
c=4.8    C=19.3°
3 0
3 years ago
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