Question

Find the equation of the line through point (−4,−4) and perpendicular to 2x+3y=3. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12).

Answer 1

Answer:

y = 3/2x + 2

Step-by-step explanation:

Step 1: Write original equation into slope-intercept form

3y = -2x + 3

y = -2/3x + 1

Step 2: Find slope of perpendicular line

Take the negative reciprocal of the other slope.

m = 3/2x

Step 3: Find b

y = 3/2x + b

-4 = 3/2(-4) + b

-4 = -6 + b

b = 2

Step 4: Rewrite perpendicular equation

y = 3/2x + 2