Answer:
I need numbers to actually calculate the problem.
Step-by-step explanation:
F(x)=a(x-h)^2+k
vertex is (h,k)
f(x)=1(x-6)^2-31
f(x)=1(x-(6))^2+(-31)
h=6
k=-31
vertex=(6,-31)
30% = 3/10 = .3
70 x .3 = 21
Answer:
0.82
Step-by-step explanation:
The question says that three percent (3 out of 100) of the rackets (racquets) produced by the company are found to be defective.
First thing to calculate is the probability that 1 in a box of 6 rackets are defective.
That probability is gotten by cross multiplying, as illustrated below;
3 - 100
x - 6
x = (6×3)/100 = 18/100 = 0.18
Since the probability of having/finding 1 defective racket in a box of 6 is 0.18, the probability of finding more than 1 (minimum of 2 and maximum of all six) defective rackets in same box would be (1 - 0.18) = 0.82
