First let's get the equation 2x - y = -4 into slope intercept form. To do this first subtract 2x to both sides:
2x - 2x - y = -4 - 2x
0 - y = -4 - 2x
-y = -4 - 2x
Y still isn't completely isolated, it still has the negative attached to it. To get rid of the negative divide both sides by -1
-y / -1 = (-4 - 2x) / -1
y = 4 + 2x
y = 2x + 4
slope intercept formula is:
y = mx + b
m is the slope
b is the y-intercept
For a line that is parallel to y = 2x + 4 and passes through point (2, 5) you will need to have the same slope (2)
This is the formula we know so far for the line parallel to y = 2x + 4:
y = 2x + b
Now we must find b
To do that you must plug in the point the line goes through ( 2, 5) in the x and y of the equation.
5 = 2(2) + b
5 = 4 + b
Now solve for b by subtracting 4 to both sides
1 = b
y = 2x + 1
^^^This line is parallel to 2x - y = -4 and goes through the point (2, 5)
Hope this helped!
~Just a girl in love with Shawn Mendes
Answer:
All you have to so is shade in 2 mini squares and your good
Answer:
slope = - 3 y-intercept = 36
Step-by-step explanation:
12x + 4y = 144 , will allow this to be done.
so 4y = - 12x + 144
now dividing both sides of the equation by 4 will give
y = - 3x + 36 , which is now in the required form
slope = - 3 and y-intercept = 36
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Answer:
f^-1(x) = √(6/(9 -x))
Step-by-step explanation:
The inverse function is the solution to ...
x = f(y)
x = 9 -6/y^2
x +6/y^2 = 9 . . . . . add 6/y^2
6/y^2 = 9 -x . . . . . subtract x
6/(9 -x) = y^2 . . . . . multiply by y^2/(9 -x)
y = √(6/(9 -x)) . . . . take the square root
Then the inverse function can be written as ...
f^-1(x) = √(6/(9 -x)) . . . . . . x < 9
