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Answer:
The distance of the first bright fringe is given as 
The distance of the second dark fringe from the central bright fringe is given as 
Explanation:
From the question we are told that
The slit separation distance is 
The distance of the slit from the screen is 
The wavelength is 
For constructive interference to occur the distance between the two slit is mathematically represented as

Where m is the order of the fringe which has a value of 1 for first bright fringe
Substituting values


For destructive interference to occur the distance between the two slit is mathematically represented as
![Y_D = [n + \frac{1}{2} ] \frac{\lambda D}{d}](https://tex.z-dn.net/?f=Y_D%20%20%3D%20%20%5Bn%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5D%20%5Cfrac%7B%5Clambda%20D%7D%7Bd%7D)
m = 2
so the formula to get the dark fringe is 
Now substituting values
![Y_D = [ 1 + \frac{1}{2} ] * \frac{633 *10^{-9} * 3.23 }{0.00115}](https://tex.z-dn.net/?f=Y_D%20%3D%20%5B%201%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5D%20%2A%20%5Cfrac%7B633%20%2A10%5E%7B-9%7D%20%2A%203.23%20%7D%7B0.00115%7D)


Answer:
the internal resistance of the cell is 0.1 ohm.
Explanation:
Given;
p.d at the terminals of a battery at no load, E₁ = 25 V
p.d at the terminals of a battery at a load, E₂ = 24 V
current through the circuit, I = 10 A
The potential drop across the circuit, V = E₁ - E₂
= 25 V - 24 V
= 1 V
The internal resistance of the cell is calculated as follows;
r = V/I
r = 1 / 10
r = 0.1 ohm
Therefore, the internal resistance of the cell is 0.1 ohm.
You have to divide 3000 miles with the 5 and it gives you a velocity of 600
Ok so basically I’m here for the points cuz I gotta quiz do in 10 minutes sorry