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Amanda [17]
3 years ago
12

I I i i i i I need Need need need neeed help help help

Mathematics
2 answers:
ki77a [65]3 years ago
5 0

Answer:

the x is 3 and the y is -3

Step-by-step explanation:

Xelga [282]3 years ago
3 0

Answer:

okay

Step-by-step explanation:

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If he has total of 20 fish,how many guppies does he have?
BaLLatris [955]

He has 20 guppies?

This is what I got from the information. Unless they had eggs.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%20%7B%205%20x%20%5E%20%7B%202%20%7D%20-%2029%20x%20-%206%20%7D%20%7B%203%20x%20%5E%20%
olganol [36]

Answer:

Step-by-step explanation:

Vertical Asymptote: x=2Horizontal Asymptote: NoneEquation of the Slant/Oblique Asymptote: y=x 3+23 Explanation:Given:y=f(x)=x2−93x−6Step.1:To find the Vertical Asymptote:a. Factor where possibleb. Cancel common factors, if anyc. Set Denominator = 0We will start following the steps:Consider:y=f(x)=x2−93x−6We will factor where possible:y=f(x)=(x+3)(x−3)3x−6If there are any common factors in the numerator and the denominator, we can cancel them.But, we do not have any.Hence, we will move on.Next, we set the denominator to zero.(3x−6)=0Add 6 to both sides.(3x−6+6)=0+6(3x−6+6)=0+6⇒3x=6⇒x=63=2Hence, our Vertical Asymptote is at x=2Refer to the graph below:enter image source hereStep.2:To find the Horizontal Asymptote:Consider:y=f(x)=x2−93x−6Since the highest degree of the numerator is greater than the highest degree of the denominator,Horizontal Asymptote DOES NOT EXISTStep.3:To find the Slant/Oblique Asymptote:Consider:y=f(x)=x2−93x−6Since, the highest degree of the numerator is one more than the highest degree of the denominator, we do have a Slant/Oblique AsymptoteWe will now perform the Polynomial Long Division usingy=f(x)=x2−93x−6enter image source hereHence, the Result of our Long Polynomial Division isx3+23+(−53x−6)

4 0
3 years ago
PLEASE HELP I HAVE 5 MINUTES LEFT AND IM HALFWAY DONE PLEASE HELP ASDHA;EFhTHS
galben [10]

Answer:

12 is 52 i think. i am not sure about 11.

Step-by-step explanation:

im so sorry i know 11:(

I hope this helps on 12 tho

7 0
3 years ago
16x+29=45<br><br> solve for x<br><br> x=
blagie [28]
16x = 45 - 29
16x = 16
x = 16/16
x = 1
8 0
3 years ago
Read 2 more answers
Suppose the supply function for a certain item is given by S(q)= (q+6)2 and the demand funtion is given by D(q)= (1000)/(q+6).
nasty-shy [4]

Answer: The equilibrium point is where; Quantity supplied = 100 and Quantity demanded = 100

Step-by-step explanation: The equilibrium point on a demand and supply graph is the point at which demand equals supply. Better put, it is the point where the demand curve intersects the supply curve.

The supply function is given as

S(q) = (q + 6)^2

The demand function is given as

D(q) = 1000/(q + 6)

The equilibrium point therefore would be derived as

(q + 6)^2 = 1000/(q + 6)

Cross multiply and you have

(q + 6)^2 x (q + 6) = 1000

(q + 6 )^3 = 1000

Add the cube root sign to both sides of the equation

q + 6 = 10

Subtract 6 from both sides of the equation

q = 4

Therefore when q = 4, supply would be

S(q) = (4 + 6)^2

S(q) = 10^2

S(q) = 100

Also when q = 4, demand would be

D(q) = 1000/(4 + 6)

D(q) = 1000/10

D(q) = 100

Hence at the point of equilibrium the quantity demanded and quantity supplied would be 100 units.

7 0
3 years ago
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