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3 years ago

A protractor can measure all types of angles except which type?

Mathematics

2 answers:

11Alexandr11 [23.1K]3 years ago

5 0

The answer is C. Reflex

tatyana61 [14]3 years ago

4 0

C reflex because it goes over 180 degrees!

You might be interested in

What are some expressions equivalent to 12x + 4?

Vanyuwa [196]

12x + 4

divide 4 from each monomial

12x/4 = 3x
4/4 = 1

4(3x + 1) is a equivalent expression.

hope this helps

5 0

3 years ago

Read 2 more answers

Wich of the following is an example of an improper fraction

saul85 [17]

If it looks like this it's Improper 21/20

6 0

3 years ago

Read 2 more answers

Steven has $25 dollars to spend. He spent $10.81, including tax, to buy a new DVD. He needs to save $10.00 but he wants to buy a

Yuliya22 [10]

(25 - 10.81) - 1.38p = 10

p = package of peanuts

25 - 10.81 = 14.19

14.19 - 1.38p = 10

Subtract 14.19 from each side

10 - 14.19 = -4.19

-1.38p = -4.19

Divide both sides by -1.38

p = 3 (roughly, but because you can only buy the whole package, this is the amount you can buy)

He can buy a maximum of 3 packages of peanuts.

6 0

2 years ago

Solve the following inequality -2x+12<36

Anestetic [448]

Answer: x > -12

-2x + 12 < 36
Subtract 12 from both sides
-2x < 24
Divide both sides by -2
Because you divided by a negative number, flip the sign
x > -12

Check
Choose a value for x
-11 > -12
-2(-11) + 12 < 36
22 + 12
34 < 36; is True

3 0

2 years ago

Read 2 more answers

A piece of cardboard has the dimensions (x + 15) inches by (x) inches with the area of 60 in 2 . Write the quadratic equation th

pochemuha

Answer:

$x^2 + 15x - 60 = 0$

The actual dimension is 18.28 by 3.28

Step-by-step explanation:

Given

Dimension:

$(x + 15)\ by\ x$

$Area = 60in^2$

Required

Determine the quadratic equation and get the possible values of x

Solving (a): Quadratic Equation.

The cardboard is rectangular in shape.

Hence, Area is calculated as thus:

$Area = Length * Width$

$60= (x + 15) * x$

Open Bracket

$60= x^2 + 15x$

Subtract 60 from both sides

$x^2 + 15x - 60 = 0$

Hence, the above represents the quadratic equation

Solving (b): The actual dimension

First, we need to solve for x

This can be solved using quadratic formula:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where

$a = 1$

$b = 15$

$c = -60$

So:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-15 \± \sqrt{15^2 - 4*1*-60}}{2*1}$

$x = \frac{-15 \± \sqrt{225 + 240}}{2}$

$x = \frac{-15 \± \sqrt{465}}{2}$

$x = \frac{-15 \± \21.56}{2}$

Split:

$x = \frac{-15 + 21.56}{2}$ or $x = \frac{-15 - 21.56}{2}$

$x = \frac{6.56}{2}$ or $x = \frac{-36.36}{2}$

$x = 3.28$ or $x = -18.18$

But length can't be negative;

So:

$x = 3.28$

The actual dimensions: $(x + 15)\ by\ x$ is

$Length =3.28 +15$

$Length =18.28$

$Width = x$

$Width =3.28$

The actual dimension is 18.28 by 3.28

3 0

3 years ago