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QveST [7]
3 years ago
9

Need help asap please! Will give brainliest!! Graph ​ x≥2 ​.

Mathematics
2 answers:
katovenus [111]3 years ago
8 0

Answer:

Step-by-step explanation:

Since x is greater than or equal to 2 the line must be solid so it includes the value 2 and the region to the right must be shaded since it is greater than 2.

inna [77]3 years ago
3 0

Answer:

Step-by-step explanation:

its the first one

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Lori rented a car for one day. The daily rental rate was $12.50 plus 25 cents per mile. The total cost of her rental was $46. Ho
Leona [35]

Answer:

The number of miles Lori drive be 134 miles .

Step-by-step explanation:

Let us assume that the number of miles Lori be x.

As given

Lori rented a car for one day.

The daily rental rate was $12.50 plus 25 cents per mile.

As 1 dollar = 100 cent

1\ cent = \frac{1}{100}\ dollar

25\ cent = \frac{25}{100}\ dollar

25\ cent = 0.25\ dollar

As given

The total cost of her rental was $46.

Than the equation becomes

46 = 12.50 + 0.25x

46 - 12.50 = 0.25x

33.5 = 0.25x

x = \frac{33.5}{0.25}

x = 134 miles

Therefore the number of miles Lori drive be 134 miles .


6 0
3 years ago
Can somebody please help me? asap
Margarita [4]
Y= 2 slope= -3 this should be right.
6 0
3 years ago
Math help pls i don’t understand how to solve this
pochemuha
<h3>Answer:    y = x+1</h3>

===================================================

Explanation:

f(x) = x^3 - 2x + 3

f ' (x) = 3x^2 - 2 ..... apply the power rule

f ' (1) = 3(1)^2 - 2 ... plug in x coordinate of given point

f ' (1) = 1

If x = 1 is plugged into the derivative function, then we get the output 1. This means the slope of the tangent line at (1,2) is m = 1. It's just a coincidence that the x input value is the same as the slope m value.

Now apply point slope form to find the equation of the tangent line

y - y1 = m(x - x1)

y - 2 = 1(x - 1)

y - 2 = x - 1

y = x - 1 + 2

y = x + 1   is the equation of the tangent line.

The graph is shown below. I used GeoGebra to make the graph.

4 0
3 years ago
The manager of a local nightclub has recently surveyed a random sample of 280 customers of the club. She would now like to deter
Lunna [17]

Answer:

z = \frac{35.6-35}{\frac{5}{\sqrt{280}}}= 2.007

p_v = P(z>2.007) = 0.0224

Since the p value is lower than the significance level given of 0.05 we have enough evidence to reject the null hypothesis on this case. And the best conclusion for this case is:

We (reject) the null hypothesis. That means that we (found) evidence to support the alternative.

Step-by-step explanation:

We have the following info given:

\bar X = 35.6 represent the sampel mean for the age of customers

\sigma = 5 represent the population standard deviation

n = 280 represent the sample size selected

We want to test if the mean age of her customers is over 35 so then the system of hypothesis for this case are:

Null hypothesis: \mu \leq 35

Alternative hypothesis \mu >35

The statistic for this case is given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing the data given we got:

z = \frac{35.6-35}{\frac{5}{\sqrt{280}}}= 2.007

We can calculate the p value since we are conducting a right tailed test like this:

p_v = P(z>2.007) = 0.0224

Since the p value is lower than the significance level given of 0.05 we have enough evidence to reject the null hypothesis on this case. And the best conclusion for this case is:

We (reject) the null hypothesis. That means that we (found) evidence to support the alternative.

5 0
3 years ago
35. Explain the difference between the reciprocal of x^2
Scorpion4ik [409]

Answer:

As you can see, the difference between the reciprocal of x^2 and the inverse of   x^2 is that \frac{1}{x^2} =x^{-2} and \sqrt{x} =x^{\frac{1}{2}.

Step-by-step explanation:

First lets find both the reciprocal of x^2 and the inverse of

Recall that the reciprocal of a value is where you take a fraction and swap the places of the terms. In the case of x^2, 1 is the denominator, so

\frac{x^2}{1} =\frac{1}{x^2}

To find the inverse of a function, you first need swap the locations of x and y in the equation

y=x^2\\\\x=y^2

Now, you need to solve for y

y^2=x\\\\y=\sqrt{x}

Now, lets rewrite each of these to better compare them

\frac{1}{x^2} =x^{-2}\\\\\sqrt{x} =x^{\frac{1}{2}

As you can see, the difference between the reciprocal of x^2 and the inverse of

7 0
3 years ago
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