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PilotLPTM [1.2K]
3 years ago
5

Maria just got a raise at work. She was making $9 per hour, but now she makes 150% of that amount.

Mathematics
2 answers:
Rudik [331]3 years ago
7 0

Answer:

First, convert 150% to the equivalent decimal 1.50 by dropping the percent sign and moving the decimal two places to the left. Then, multiply 9 by 1.50 to get 13.50. Maria now makes $13.50 per hour.

Step-by-step explanation:

edge2020

Stolb23 [73]3 years ago
5 0

Answer:

13.50

Step-by-step explanation:

150. x

___ ___ x = $13.50 per hour

100. 9

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The weekly salaries of a sample of employees at the local bank are given in the table below. Employee Weekly Salary Anja $245 Ra
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The variance for the data is  17,507. 5.

Given

The weekly salaries of a sample of employees at the local bank are given in the table below.

Employee Weekly Salary Anja $245 Raz $300 Natalie $325 Mic $465 Paul $100.

<h3>Variance</h3>

Variance is the expected value of the squared variation of a random variable from its mean value, in probability and statistics.

The mean value of the salaries of employees is;

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2 years ago
Contains the x intercept of 4x-y=8 and the point (-4,3)
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7 0
3 years ago
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The amount of time all students in a very large undergraduate statistics course take to complete an examination is distributed c
Anestetic [448]

Answer:

a) The mean is \mu = 60

b) The standard deviation is \sigma = 9

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.

This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when X = 55.5, Z = -0.5

So

Z = \frac{X - \mu}{\sigma}

-0.5 = \frac{55.5 - \mu}{\sigma}

-0.5\sigma = 55.5 - \mu

\mu = 55.5 + 0.5\sigma

The probability a student selected at random takes no more than 71.52 minutes to complete the examination equals 0.8997.

This means that when X = 71.52, Z has a pvalue of 0.8997. This means that when X = 71.52, Z = 1.28

So

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{71.52 - \mu}{\sigma}

1.28\sigma = 71.52 - \mu

\mu = 71.52 - 1.28\sigma

Since we also have that \mu = 55.5 + 0.5\sigma

55.5 + 0.5\sigma = 71.52 - 1.28\sigma

1.78\sigma = 71.52 - 55.5

\sigma = \frac{(71.52 - 55.5)}{1.78}

\sigma = 9

\mu = 55.5 + 0.5\sigma = 55.5 + 0.5*9 = 55.5 + 4.5 = 60

Question

The mean is \mu = 60

The standard deviation is \sigma = 9

6 0
2 years ago
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