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umka2103 [35]
3 years ago
11

What are the factors of the trinomial? Check all that apply

Mathematics
1 answer:
zmey [24]3 years ago
5 0

For this case, the first thing we should do is write the trinomial.

To do this, we add similar terms.

We have then:

x ^ 2 + 2x - 7x - 7 - 7

Then, rewriting the trinomial we have:

x ^ 2 + 2x - 7x - 14

Then, the trinomial is given by:

x ^ 2 - 5x - 14

Factoring we have:

x (x + 2) -7 (x + 2)

Rewriting we have:

(x + 2) (x-7)

Answer:

The trinomial factors are given by:

(x + 2)\\(x-7)

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The first 6 nonzero multiples of 5
Vikentia [17]
<span>5: 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75.... </span>
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Find the unit rate. 6 2/5 revolutions in 2 2/3 seconds
Brums [2.3K]
The unit rate will be in revolutions per second. That means divide number of revolutions by number of seconds.

first convert from mixed fraction.
6 2/5 = 32/5 revolutions
2 2/3 = 8/3 seconds

32/5 ÷ 8/3
flip multiply
32/5 × 3/8 = 12/5 revolutions per second

12/5 = 2 2/5 revolutions per second


6 0
4 years ago
What is the coefficient of the term of degree 5 in the polynomial below? 3x6 + 5 - x2 + 4x5 - 9x A. 5 B. 4 C. 3 D. 6
liq [111]
4x^5 is a term of degree 5, and its coefficient is 4
6 0
4 years ago
Read 2 more answers
Where on the coordinate plane is the point (-85, 52) located?
marysya [2.9K]

Answer:

go to the left to -85 then go up to 52.

Step-by-step explanation:

x=-85

y=52

7 0
2 years ago
Read 2 more answers
The line on the graph passes through the points A (0, 6) and B (3, 0).
Natali5045456 [20]

The equation for the line passing through point A and perpendicular to AB will be y-0.5x=6, the gradient of line AB is -2, and the gradient of a line perpendicular to AB is 0.5.

<h3 /><h3>What is the slope or gradient?</h3>

A numerical assessment of a line's angle relative to the ground is known as the slope.

Given data;

m₁ is the slope of line AB

m₂ is the slope of a line perpendicular to AB

The coordinate points are,

A,(x₁,y₁)= (0, 6)

B,(x₂,y₂)=(3, 0).

The gradient of line AB;

\rm m_{{1} }= \frac{y_2-y_1}{x_2-x_1} \\\\ \rm m_{{1} }= \frac{0-6}{3-0} \\\\ m_{{1} }=-2

The slope of the lines has a perpendicular relation is -1;

m₁ × m₂ = -1

(-2) × m₂ = -1

m₂ = 1/2

m₂ = 0.5

The equation of the line passing through point A and perpendicular to AB;

(y - y₁) = m₂(x-x₁)

(y-6)=0.5(x-0)

y-6 = 0.5 x

y-0.5x=6

Hence, the gradient of line AB, the gradient of a line perpendicular to AB, and the equation of the line passing through point A and perpendicular to AB will be -2,0.5 and y-0.5x=6.

To learn more about the slope, refer to the link;

brainly.com/question/3605446

#SPJ1

4 0
2 years ago
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