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Tatiana [17]
3 years ago
12

Describe a situation you’re familiar with where one quantity changes constantly in relation to another

Mathematics
1 answer:
Crank3 years ago
8 0

Answer:

One such situation is the amount of money in excess you paid for an item and the amount of change you will get. Another such scenario would be the total numbers of hours with respect to the total number of days. With more days, there will be more time hence more hours.

Step-by-step explanation:

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I need help fast .....​
gizmo_the_mogwai [7]

Answer:

(0,6)

Step-by-step explanation:

So x=0, so plug in 0 for x. 5(0) + 6 - (0)^2 = 6

8 0
3 years ago
The number n when increased
Olin [163]

Answer:

Number n increased by 18 = n +18

Number is 2 less than 5 times n= 5n -2

They are same =>  n +18 = 5n -2

Option B

[ n + 18 = 5n -2

18 +2 =5n - n

20 = 4n

n = 5

Lets check 5+18 = 5*5 - 2

                 23 = 23]

6 0
3 years ago
Need help please !!!!!!
11Alexandr11 [23.1K]
A perfect square must be hidden within all of those radicands in order to simplify them down to what the answer is.  \sqrt{192}= \sqrt{64*3}= 8\sqrt{3}.  \sqrt{80}= \sqrt{16*5}=4 \sqrt{5}.  \sqrt{12288}= \sqrt{4096*3}=64 \sqrt{3}.  The rules for adding radicals is that the index has to be the same (all of our indexes are 2 since we have square roots), and the radicands have to be the same.  In other words, we cannot add the square root of 4 to the square root of 5.  They either both have to be 4 or they both have to be 5.  So here's what we have thus far: 8 \sqrt{3}+4 \sqrt{5}+64 \sqrt{3}.  We can add 8 \sqrt{3} and 64 \sqrt{3} to get 72 \sqrt{3}.  That means as far as our answer goes, A = 72 and B = 4, or (72, 4), choice a.
5 0
3 years ago
X + 5y - 4z = 10<br> -* - y = -6<br> -6x+2y = -20
Brums [2.3K]

Answer:

567

Step-by-step explanation:

8 0
3 years ago
I need help with this question pleas urgent!
BaLLatris [955]

Answer:

75.5

Step-by-step explanation:

To calculate the mean we use

mean = \frac{score}{count}

To calculate the mean for class B we require their score

Using the mean for class A

\frac{score}{25} = 67.8 ( multiply both sides by 25 )

score = 67.8 × 25 = 1695

Similarly using the mean for all 55 students

\frac{totalscore}{55} = 72 ( multiply both sides by 55 )

total score = 72 × 55 = 3960

Hence score for class B = 3960 - 1695 = 2265

mean for class B = \frac{2265}{30} = 75.5

3 0
3 years ago
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