Answer:
All real numbers / (-∞, ∞) / R
Step-by-step explanation:
The equasion provided is a linear equasion meaning it can be written in the y=ax+b format, where both a and b are real numbers. All linear eqasions have a range of all real numbers, you can write this using the three solutions provided.
You can solve this two ways, number one would be to put this in a graphing calculator and number two would be reducing the equasion to the y=ax+b format.
<h2>Method 1:</h2>
look at image provided. The app is PhotoMath.
<h2>Method 2:</h2>
Write the equasion:
y = -2x - 6x + 1
Collect like terms:
y = -8x + 1
This now proves that the equasion is linear becuase you can write it in the y=ax+b format. a being -8 and b being 1.
The correct answer is 26.6 repeating.
You do 400/15
Answer:
Y=3n+10
Step-by-step explanation:
Hello,
The first thing we should know is that this exercise is modeled by equating a straight line, which is Y = mx + b
where Y, is the value in milligrams of the patient's dose, b is the intercept with the Y axis and x is the number of hours that pass, and m is the slope, taking into account the above we infer the following equation
Y=mn+b
Now what we do is find every 2 points of the line using the problem data, in order to find the complete equation and the slope,
N1=0 Y1=10mg
N2=1 Y2=10mg+4mg=14mg
b is the value of Y when n = 0 therefore b = 10
Now we remember the equation of the slope
the ecuation is
Y=4n+10
Finally, the problem explains that the body loses 25% of the medication, therefore we multiply the equation by the 75% that remains in the body taking into account that the initial dose for N = 0 must be 10mg.
final ecuation
Y=3n+10
Sin³ x-sin x=cos ² x
we know that:
sin²x + cos²x=1 ⇒cos²x=1-sin²x
Therefore:
sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0
sin³x=z
z³+z²-z-1=0
we divide by Ruffini method:
1 1 -1 -1
1 1 2 1 z=1
-------------------------------------
1 2 1 0
-1 -1 -1 z=-1
--------------------------------------
1 1 0 z=-1
Therefore; the solutions are z=-1 and z=1
The solutions are:
if z=-1, then
sin x=-1 ⇒x= arcsin -1=π+2kπ (180º+360ºK) K∈Z
if z=1, then
sin x=1 ⇒ x=arcsin 1=π/2 + 2kπ (90º+360ºK) k∈Z
π/2 + 2kπ U π+2Kπ=π/2+kπ k∈Z ≈(90º+180ºK)
Answer: π/2 + Kπ or 90º+180ºK K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
Answer:
Step-by-step explanation:
1) Factor using polynomial division.
2) Rewrite in the form , where a = x and b = 5.
3) Use Square of Sum: .