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Lynna [10]
3 years ago
10

According to the fundamental theorem of algebra, how many zeros does the function f(x) = 15x12 + 41x9 + 13x2 − 10 have?

Mathematics
1 answer:
tatiyna3 years ago
5 0
<span>According to the fundamental theorem of algebra, the function f(x) = 15x</span>¹²<span> + 41x</span>⁹<span> + 13x</span>²<span> − 10 have 12 zeros.

Fundamental Theorem of Algebra states that "any polynomial of degree n has n roots, but we may need to use complex numbers".

The degree that we need to identify in a polynomial is the largest exponent used in the equation. In this case, 15x</span>¹², has the largest exponent. It is the degree of n used to determine the number of zeros. Thus, n = 12 so number of zero is also 12.
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