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3 years ago

What is 12.75 in a mixed number

Mathematics

2 answers:

ANTONII [103]3 years ago

6 0

12.75=12 3/4

Hope this helps!!!!!!!!!!!!

kap26 [50]3 years ago

4 0

12.75
12= whole number
.75= is in the hundred place value
so 12 75/100
simplify to 12 3/4

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Money Spent on Road Repair A politician wishes to compare the variances of the amount of money spent for road repair in two diff

Mkey [24]

Answer:

(A) Null Hypothesis, $H_0$ : $\sigma_1^{2} =\sigma_2^{2}$ {means that there is no significant difference in the variances of the amounts spent in the two counties}

Alternate Hypothesis, $H_A$ : $\sigma_1^{2} \neq \sigma_2^{2}$ {means that there is a significant difference in the variances of the amounts spent in the two counties}

(B) The F-table gives critical values of 0.359 and 2.781 for (14,17) degrees of freedom for the two-tailed test.

(C) The value of the F-test statistic is 0.611.

(D) We conclude that there is no significant difference in the variances of the amounts spent in the two counties.

Step-by-step explanation:

We are given that a politician wishes to compare the variances of the amount of money spent on road repair in two different counties.

The data are given here below;

County A County B

s1 = $11,596 s2 = $14,837

n1 = 15 n2 = 18

Let $\sigma_1^{2}$ = variances of the amounts spent in County A.

$\sigma_2^{2}$ = variances of the amounts spent in County B.

(A) So, Null Hypothesis, $H_0$ : $\sigma_1^{2} =\sigma_2^{2}$ {means that there is no significant difference in the variances of the amounts spent in the two counties}

Alternate Hypothesis, $H_A$ : $\sigma_1^{2} \neq \sigma_2^{2}$ {means that there is a significant difference in the variances of the amounts spent in the two counties}

The test statistics that would be used here Two-sample F-test statistics distribution;

T.S. = $\frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }$ ~ $F__n_1_-_1,_ n_2_-_1$

where, $s_1$ = sample standard deviation for County A = $11,596

$s_2$ = sample standard deviation for County B = $14,837

$n_1$ = sample size for County A = 15

$n_2$ = sample size for County B = 18

(B) Now at 0.05 level of significance, the F-table gives critical values of 0.359 and 2.781 for (14,17) degrees of freedom for the two-tailed test.

(C) So, the test statistics = $\frac{11,596^{2} }{14,837^{2} } \times 1$ ~ $F__1_4,_ 1_7$

= 0.611

The value of the F-test statistic is 0.611.

Now, as we can see that our test statistics lie within the range of critical values of F, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

(D) Therefore, we conclude that there is no significant difference in the variances of the amounts spent in the two counties.

7 0

4 years ago

How do I solve 2t<-4 or 7t>49

laiz [17]

2t<-4
t< (-4/2)
t<-2

just treat the greater and less than signs as equal signs

5 0

3 years ago

Brainliest 5 stars Thanks! Use the Remainder Theorem.

GalinKa [24]

Answer:

If f(1)=0 then 1 is a root and (x-1) is a factor of f(x). divide f(x) by (x-1). you now have a quadratic. Find its roots by methods you know.

actually this factors by grouping:

f(x)=x³+3x²-x-3

= x²(x+3)-1(x+3)

=(x+3)(x²-1)

=(x+3)(x-1)(x+1) // difference of squares

By zero product property roots are

-3, -1, 1

5 0

3 years ago

The mean of 100 numerical observation is 51.18 what is the value of the sum of all 100 numbers

malfutka [58]

The "mean" is the same thing as the "average".

To get the average, you add up all the numbers on the list,
then divide the big sum by the number of items on the list.

If there are 100 numbers on the list, then in order to find their average,
you would add up all 100 numbers, then divide the big sum by 100.

If you wound up with an average of 51.18, then you must have had
5,118 just before you divided it by 100. So the big sum is 5,118.

8 0

3 years ago

Please help with this will give BRAINLIST to best answer

Aleonysh [2.5K]

Answer:

pxp^8=12

Step-by-step explanation:

7 0

3 years ago