What you have here is a situation with two <em>similar triangles.
</em>The triangle in the lower left is similar to the triangle in the upper right - I've included an image with "cutouts" of those triangles so you can see the similarities. Similar triangles have a very important property: <em>the ratios of their corresponding sides are equivalent</em>. Here, we can set up a ratio between the sides of length 64 and x on the larger triangle, and the corresponding sides of length x and 36 on the smaller triangle. Setting the two equal to each other, we have

Multiplying both sides of the equation by 36 and x, we get

finally, we take the square root of both sides of the equation to find x:

Divide both sides of the equation by 5.2

Move the constant to the right-hand side and change its sign

Add the decimals

4. Option 3, a has length of infinity and mn does not split a, a splits mn
5. Option 2, only 1 possibility, since it has to split mn into equal parts
Answer:
7.45
Step-by-step explanation:
We are given a right triangle with one side length known and an angle know so we can use some trigonometry.
You need to find the hypotenuse so you are going to use either sine or cosine.
Since the adjacent from the angle is given (SOH-CAH-TOA) we can use cosine so,
cos(20) = 7/h
=>h = 7/cos(20)
=> 7.44924
=> 7.45
Alright, lets get started.
The answer Sandra got is correct that is zero but there are some mistakes she made while writing steps.
Incorrect step
Because as per even/odd identity,
Cot (-Θ) = - cot (Θ)
Hence

Now,
It could be written as


0
Hence the answer is 0. : Answer
Hope it will help :)