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3 years ago

I dont know on this one, its complicated

Mathematics

2 answers:

balandron [24]3 years ago

7 0

A = a^2 = 121
so a = 11

answer
11 inches

I am Lyosha [343]3 years ago

6 0

If you knew the squares of the numbers between 10 and 20, you would not describe this as complicated.
.. (11 in)^2 = 121 in^2

The side length is 11 inches.

_____
A square is a special rectangle. Its length is equal to its width. The area of any rectangle is the product of length and width, but because those are the same for a square, its area is the square of the side length. (square ... square, do you see any relation?)

Finding a square root is the process of finding a number that multiplies by itself to give a particular result. You want to find the square root of 121, so you will know the value (11) that multiplies by itself to give 121. If you don't already know this number, your calculator will find it for you.

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Use PEMDAS and integer rules to evaluate the numeric expression -6×-6+-6-6

spayn [35]

You start with -6 times -6 which equals 36,
from there subtract six (which would give you 30) and then subtract another 6 giving you a final answer of 24

answer: 24

4 0

4 years ago

Read 2 more answers

Please help i need to know how to do it, plz tell me how you get it<br><br><br><br> (4-i)(6-6i)

Aleksandr-060686 [28]

18-30i is the awnser

7 0

3 years ago

Jesse and Amir were assigned the same book to read. Jesse started reading on Saturday, and he is reading 30 pages a day. Amir di

bezimeni [28]

1. An equation representing the number of days Amir has been reading and the number of pages he has read is <u>y = 35x</u>.

2. An equation representing the number of days Jesse has been reading and the number of pages she has read is <u>y = 30 + 30x</u>.

3. The system of equations from 1 and 2 is y = 35x and y = 30 + 30x.

4. At the end of Friday, after solving the equations, both Jesse and Amir read <u>210 pages each</u>, with Jesse spending <u>7 days</u> and Amir <u>6 days</u>.

5. For Jesse and Amir, the equation solutions are <u>y is 210</u> pages and <u>x is 6 days</u>.

6. After solving the equations, it will take Amir <u>6 days</u> to catch up with Jesse and each person must have read <u>210 pages</u> or a total of <u>420 pages</u>.

<h3>What is a system of equations?</h3>

A system of equations involves using more than one equation solved simultaneously.

Jesse's reading rate per day = 30 pages

Amir's reading rate per day = 35 pages

The number of pages read by Jesse, y = 30 + 30x

The number of pages read by Amir, y = 35x

Where x = the number of days they have been reading

<h3>Solving the equations:</h3>

y = 30 + 30x and y = 35x

35x = 30 + 30x

35x - 30x = 30

5x = 30

x = 6 (30/5)

<h3>Jesse:</h3>

y = 30 + 30x

y = 30 + 30(6)

y = 210

y = 35x

y = 35(6)

y = 210

Learn more about simultaneous equations at brainly.com/question/16763389

#SPJ1

5 0

1 year ago

Find the area of each figure. Round to the nearest tenth if necessary.

Gnesinka [82]

Shape 1: TRIANGLE

Formula: A = 1/2 x bh

1/2 x (10)(5) = 25

AREA: 25 square yards

Shape 2: RECTANGLE

Formula: A = lw

(12)(10) = 120

AREA: 120 square yards

Sum (ADD)

25 yd^2 + 120 yd^2 = 145 yd^2

The area of the composite figure is 145 yd^2

8 0

3 years ago

Read 2 more answers

Find the particular solution of the differential equation?<br> /=5^3+9^2, when =1, =8

kipiarov [429]

Answer:

$\displaystyle s = \frac{5t^4}{4} + \frac{9}{t} - \frac{9}{4}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

<u>Algebra I</u>

Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

<u>Calculus</u>

Derivatives

Derivative Notation

Solving Differentials - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Step-by-step explanation:

*Note:

Ignore the Integration Constant C on the left hand side of the differential equation when integrating.

<u>Step 1: Define</u>

$\displaystyle \frac{ds}{dt} = 5t^3 + \frac{9}{t^2}$

t = 1

s = 8

<u>Step 2: Integrate</u>

[Derivative] Rewrite [Leibniz's Notation]: $\displaystyle ds = (5t^3 + \frac{9}{t^2})dt$
[Equality Property] Integrate both sides: $\displaystyle \int {} \, ds = \int {(5t^3 + \frac{9}{t^2})} \, dt$
[Left Integral] Reverse Power Rule: $\displaystyle s = \int {(5t^3 + \frac{9}{t^2})} \, dt$
[Right Integral] Rewrite [Integration Property - Addition]: $\displaystyle s = \int {5t^3} \, dt + \int {\frac{9}{t^2}} \, dt$
[Right Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle s = 5\int {t^3} \, dt + 9\int {\frac{1}{t^2}} \, dt$
[Right Integrals] Rewrite [Exponential Rule - Rewrite]: $\displaystyle s = 5\int {t^3} \, dt + 9\int {t^{-2}} \, dt$
[Right Integrals] Reverse Power Rule: $\displaystyle s = 5(\frac{t^4}{4}) + 9(\frac{t^{-1}}{-1}) + C$
[Right Integrals] Rewrite [Exponential Rule - Rewrite]: $\displaystyle s = 5(\frac{t^4}{4}) + 9(\frac{1}{t}) + C$
Multiply: $\displaystyle s = \frac{5t^4}{4} + \frac{9}{t} + C$

<u>Step 3: Solve</u>

Substitute in variables: $\displaystyle 8 = \frac{5(1)^4}{4} + \frac{9}{1} + C$
Evaluate exponents: $\displaystyle 8 = \frac{5}{4} + \frac{9}{1} + C$
Divide: $\displaystyle 8 = \frac{5}{4} + 9 + C$
Add: $\displaystyle 8 = \frac{41}{4} + C$
[Subtraction Property of Equality] Isolate <em>C</em>: $\displaystyle \frac{-9}{4} = C$
Rewrite: $\displaystyle C = \frac{-9}{4}$

Particular Solution: $\displaystyle s = \frac{5t^4}{4} + \frac{9}{t} - \frac{9}{4}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Differentials Equations and Slope Fields

Book: College Calculus 10e

3 0

3 years ago