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defon
4 years ago
14

I don't know this 17/21 - 2/10

Mathematics
2 answers:
Naily [24]4 years ago
5 0

Answer:64/105

Step-by-step explanation:

Find the lcm of 21 and 10.

170/210 - 42/210

128/210

64/105

Maksim231197 [3]4 years ago
3 0

Answer:

64/105

Step-by-step explanation:

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emmasim [6.3K]

Bit: Computers deal with binary digits, or bits for short. A bit can be 0 or 1, equivalent or off or on.

Byte: One byte is eight binary digits, such as 1111001.

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Megabyte (MB): 1024KB equals one megabyte (MB).

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I Hope this Helps!!

Tell me if this is wrong please

3 0
3 years ago
Will give brainliest, thanks, and 5 stars! LOTS OF POINTS! 50 POINTS!
sweet-ann [11.9K]

Answer/Step-by-step explanation:

 All of the solutions to the equation 3x^2 - 12 = 0 are x = 12 and x = -2

Answer: False

Explanation:

3x^2-12+12=0+12

3x^2=12

\frac{3x^2}{3}=\frac{12}{3}

x^2=4

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{4},\:x=-\sqrt{4}

x=2,\:x=-2

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

There are two unique solutions to the equations (x-3)^2 = 16

Note: Each variable in the matrix can have only one possible value, and this is how you know that this matrix has one unique solution.

Answer: True

Explanation:

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=7,\:x=-1

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Ths solutions for the equation 2(x-3)^3 - 18 = 0 are x = 6 and x = 0

Answer: False

Explanation:

2\left(x-3\right)^3-18+18=0+18

2\left(x-3\right)^3=18

\frac{2\left(x-3\right)^3}{2}=\frac{18}{2}

\left(x-3\right)^3=9

\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

=\sqrt[3]{9}+3,\:x=\frac{6-\sqrt[3]{9}}{2}+i\frac{\sqrt[3]{9}\sqrt{3}}{2},\:x=\frac{6-\sqrt[3]{9}}{2}-i\frac{\sqrt[3]{9}\sqrt{3}}{2}

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~The solutions for the equation 2(x-5)^2-8=0 are x = 7 and x = -7

Answer: False

Explanation:

2\left(x-5\right)^2-8+8=0+8

2\left(x-5\right)^2=8

\frac{2\left(x-5\right)^2}{2}=\frac{8}{2}

\left(x-5\right)^2=4

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=7,\:x=3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation (x + 3)^2-25 = -8 are x = 2 and x = -8

Answer: False

Explanation:

\left(x+3\right)^2-25+25=-8+25

\left(x+3\right)^2=17

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{17}-3,\:x=-\sqrt{17}-3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation 2(2x-1)^2=18 are x = 5 and x = -4

Answer: False

Explanation:

\frac{2\left(2x-1\right)^2}{2}=\frac{18}{2}

\left(2x-1\right)^2=9

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=2,x=-1

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The only solution for equation (2x-1)^2-49=0 is x = 4

Answer: False
Explanation:

\left(2x-1\right)^2-49+49=0+49

\left(2x-1\right)^2=49

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=4,\:x=-3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation 3(x+2)^2 - 3 = 0 are x = -3 and x = -1

Answer: True
Explanation:

3\left(x+2\right)^2-3+3=0+3

3\left(x+2\right)^2=3

\frac{3\left(x+2\right)^2}{3}=\frac{3}{3}

\left(x+2\right)^2=1

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=-1,\:x=-3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation 5x^2 - 180 = 0 are x = 6 and x  = -6

Answer: True

Explanation:

5x^2-180+180=0+180

5x^2=180

\frac{5x^2}{5}=\frac{180}{5}

x^2=36

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{36},\:x=-\sqrt{36}

x=6,\:x=-6

<u><em>~Lenvy~</em></u>

7 0
3 years ago
Luiza starts collecting rare coins. In the first month of her collection, she has 25 coins. Each month since then, she has added
almond37 [142]

Answer: 71 coins

Step-by-step explanation:

First and foremost, we should note that:

12 months = 1 year

2 years = 12 × 2 = 24 months

Since she has 25 coins in her first month and adds 2 coins to her monthly collections, this means that she has 23 more months. This can be expressed as:

= 25 + 2x

where, x = number of months

= 25 + 2(23)

= 25 + 46

= 71 coins

She will have 71 coins after 2 years.

4 0
3 years ago
.
Neko [114]
Add the number of miles it takes to get from Austin to Dallas and add that to the number of miles it takes to go from Dallas to Oklahoma. 181+206=387
3 0
3 years ago
Solve the system.<br> y = 2x + 5<br> y=-3x<br><br> What is the solution?
Alexxx [7]

Answer:

x=−1 and y=3 or (-1,3)

WORK:

Let's solve your system by substitution.

y=2x+5;y=−3x

Step: Solve y=2x+5 for y:

y=2x+5

Step: Substitute 2x+5 for y in y=−3x:

y=−3x

2x+5=−3x

2x+5+3x=−3x+3x (Add 3x to both sides)

5x+5=0

5x+5+−5=0+−5(Add -5 to both sides)

5x ÷ 5 = -5÷5 (divide both sides with 5)

x=−1

Step: Substitute −1 for x in y=2x+5:

y=2x+5

y=(2)(−1)+5

y=3(Simplify both sides of the equation)

Answer:

x=−1 and y=3

(Incase you needed to show your work)

Hope this helps :)

8 0
3 years ago
Read 2 more answers
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