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4 years ago

7x+8(x+1/4)=3(6x-9)-8 need a solution for this problem

1 answer:

6 0

Remember to do the same thing to both sides

use distributive prpoerty which is
a(b+c)=ab+ac so
pemdas
multiplication
8(x+1/4)=8x+8/4=8x+2
3(6x-9)=18x-27

now we have7x+8x+2=18x-27-8
add like terms
15x+2=18x-35
subtract 15x from both sides
2=3x-35
add 35 to both sides
37=3x
divide both sides by 3
37/3=x
12 and 1/3=x

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Vesnalui [34]

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3 years ago

Leticia simplified an expression. Her work is shown below.

victus00 [196]

Leticia made a mistake in her step 2. She did subtraction before multiplication.

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The expression can be simplified as follows;

4.5 ÷ 0.25 + 2.5 - 0.75 × 8

Hence, using Pemdas rule,

4.5 ÷ 0.25 + 2.5 - 0.75 × 8

18 + 2.5 - 0.75 × 8

18 + 2.5 - 6 = 14.5

Therefore, she made mistake in her step 2 because she was suppose to solve the multiplication before subtraction.

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2 years ago

Use a unit multiplier to convert<br> $12.00 per hour to dollars per<br> minute.

il63 [147K]

Answer:

$00.20 per min

Step-by-step explanation:

Technically $12.00 per hour is $12.00 per 60 min. So now take that and divide $12.00 by 60 and you get 20 cents per min.

6 0

3 years ago

Read 2 more answers

Which Equations could verify the solution to the equation -48=-7x-13

arlik [135]

Answer:

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Step-by-step explanation:

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4 years ago

Vladimir says that the equation of the line that passes through points (-5,-3) and (10,9) is y=4/5x+1 Robyn says that the line p

Talja [164]

Answer:

Robyn and Vladimir both are correct.

Step-by-step explanation:

Vladimir says that the equation of the line the passes through points (-5, -3) and (10,9) is y = $\frac{4}{5}$ x + 1

Let's find the equation of line

Slope of the line passing through ( -5, -3 ) and (10, 9 )

$m=\frac{y-y'}{x-x'}=\frac{9+3}{10+5}=\frac{12}{15}=\frac{4}{5}$

So equation will be y = $\frac{4}{5}$ x + c

Since the line passes through (-5, -3)

so (-3) = $\frac{4}{5}$ x (-5) + c

(-3) = -4 + c

c = -3 +4 = 1

So equation should be y = $\frac{4}{5}$ x +1

Therefore, Vladimir is correct.

Robyn says this line is passing through (-10,-7) and (-15, -11)

Slope $m=\frac{y-y'}{x-x'}=\frac{-11+7}{15+10}=\frac{-4}{-5}=\frac{4}{5}$

equation is y = $\frac{4}{5}$ x + c

Since this line passes through (-10 -7)

so (-7) = $\frac{4}{5}$ x (-10) + c

-7 = -8 + c ⇒ c = 8 - 7 = 1

Equation of the line will be y = $\frac{4}{5}$ x + 1

So Robyn and Vladimir both are correct.

5 0

3 years ago

Read 2 more answers