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scoundrel [369]
3 years ago
5

What is 6 qt 15 fl oz - 4 pt 4 fl oz =____pt____fl oz

Mathematics
2 answers:
yan [13]3 years ago
6 0

Answer:

4.0 = 64. 5.0 = 80. pints to fluid ounces. 6.0 = 96. 7.0 = 112. 8.0 = 128. 9.0 = 144. 10 = 160. 1 US fluid ounce ( fl oz) = 0.0625 US pints ( pt) = 0.03125 US quarts (qt) = 0.125 US cups (c) = 6 US teaspoons = 2 US tablespoons = 29.5735296 milliliters (ml) = 0.0295735296 liters (l).

Step-by-step explanation:

FinnZ [79.3K]3 years ago
3 0

Answer:

2 pt 11 fl oz

Step-by-step explanation:

You might be interested in
Find real solutions x-(4-8x)^0.5=0
Vadim26 [7]

Answer:

There are no real roots for this equation.

Step-by-step explanation:

The only solution is irrational: x-√(4-8x)=0

I have provided a graph to help you with this problem.

Hope this helps! :)

5 0
3 years ago
SAT scores are normed so that, in any year, the mean of the verbal or math test should be 500 and the standard deviation 100. as
vovangra [49]

Answer:

a) P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)

P(Z>1.25)=1-P(Z

b) P(400

P(-1

P(-1

c) z=-0.842

And if we solve for a we got

a=500 -0.842*100=415.8

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the SAT scores of a population, and for this case we know the distribution for X is given by:

X \sim N(500,100)  

Where \mu=500 and \sigma=100

We are interested on this probability

P(X>625)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)

And we can find this probability using the complement rule and with the normal standard table or excel:

P(Z>1.25)=1-P(Z

Part b

We are interested on this probability

P(400

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(400

And we can find this probability with this difference:

P(-1

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-1

Part c

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.8   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.2 of the area on the left and 0.8 of the area on the right it's z=-0.842. On this case P(Z<-0.842)=0.2 and P(Z>-0.842)=0.8

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.842

And if we solve for a we got

a=500 -0.842*100=415.8

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.  

8 0
3 years ago
What’s the answer pleazzzzz helplllllll 9m^2-4m-6 by 3m
dlinn [17]

Answer

D. 3m - 4/3 -2/m


<u>Explanation</u>

(9m²-4m-6) ÷ 3m  = 9m²/3m - 4m/3m - 6/3m

Carry out the division, each term is divided by 3m.

9m²/3m = 3m

- 4m/3m = -4/3

- 6/3m = - 2/m

Finally you will get,

<em>3m - 4/3 -2/m</em>

5 0
3 years ago
a full-time employee who works 40 hours per week earns 29.85 per hour estimate the person's annual income
balu736 [363]
There are 52 weeks in a year. The question is asking how much is the annual salary.
8 0
3 years ago
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blondinia [14]
A-owowowowwqzlzlz +eiwiiwiwow
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3 years ago
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