Triangle ABD is i<span>nscribed in circle and </span>has hypotenuse as circle's diameter so angle ABD must be 90°
Since it is parallelogram, ∠ABD = ∠BDC = 90° and it is given that ∠ADB = 30°
So we have ∠CDO = ∠CDB + ∠ADB = 30° + 90° = 120°
Final answers: ∠CDO = 120° and ∠ABD = 90°
Hey!
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We know that (a = -3), (b = 2), (c = 5), and (d = -4)
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Question 6:
= 5ac - 2b
= 5(-3)(5) - 2(2)
= 5(-15) - 4
= -75 - 4
<u>= -79</u>
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Question 7:
= ab/d
= (-3)(2)/-4
= -6/-4
<u>= 1 1/2</u>
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Hope this helped, good luck!
The answer is $113 because you add the money
B. Angle 2 and angle seven are actually alternate exterior angles.
Answer:
It is 5 or x>5
Step-by-step explanation:
