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3 years ago

3(2a + 1) = -5(a + 6)

1 answer:

4 0

3(2a+1)=-5(a+6)
First expand the brackets.
6a+3=-5a-30
Now add 5a to both sides.
11a+3=-30
Then subtract 3 from both sides.
11a=-33
Finally divide both sides by 11.
a=- 33/11
=-3

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A number that can be written as a fraction is a_______

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A rational number can be writen as a fraction.

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3 years ago

Does anyone know the answer

lesya [120]

If the square translates to 7 units on the right and 6 units downwards, the following changes will be made:

Point S will have the coordinates of (3, -5).

Point R will have the coordinates of (-1, -5).

Point U will have the coordinates of (-1, -9).

Point T will have the coordinates of (3, -9).

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2 years ago

Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t

MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6. $\overline 6$

Given that 6. $\overline 6$ > 0, we have;

At the maximum volume, the width of the block, w = 6. $\overline 6$ cm ≈ 6.7 cm

The maximum volume, $V_{max}$ , is therefore given when w = 6. $\overline 6$ cm = 20/3 cm as follows;

V = 10·w² - w³

$V_{max}$ = 10·(20/3)² - (20/3)³ = 4000/27 = 148. $\overline {148}$

The maximum volume, $V_{max}$ = 148. $\overline {148}$ cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³