a) These telescopes must make observations above much of the water vapor in the atmosphere because water can block infrared rays.
Explanation:
Ground- based infrared telescopes are placed in a high altitudes dry climates because the telescopes must make observations above much of water vapor since they cut and block them off.
- Telescopes are devices that are used to observe very distant objects.
- An infrared telescope is sensitive to infrared rays.
- Infrared rays are part of the electromagnetic radiations.
- These rays are usually blocked off by the presence of water vapor.
- Desert areas that lacks water vapor in the atmosphere are the most desired for sighting such facilities.
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Explanation:
13. 8,448 = 8,450 (round up, 8 more than 5)
14. 89.32 = 89.3 (round down, 2 less than 5, 0 is not needed)
15. 0.05678 = 0.0568 (round up, 8 more than 5, 0 in front are not significant)
Well, since matter doesn't simply poof into existence and water is H2O, 465g of water is a combination of 52.0g of H and 413g O
Tap water contains many dissolved ions that are required to carry an electric current, whilst distilled water contains no or relatively low amounts of dissolved ions. the absence of ions in the distilled water accounts for the low to zero conductivity of the water
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Original molarity was 1.7 moles of NaCl
Final molarity was 0.36 moles of NaCl
Given Information:
Original (concentrated) solution: 25 g NaCl in a 250 mL solution, solve for molarity
Final (diluted) solution: More water is added to make the new total volume 1.2 liters, solve for the new molarity
1. Solve for the molarity of the original (concentrated) solution.
Molarity (M) = moles of solute (mol) / liters of solution (L)
Convert the given information to the appropriate units before plugging in and solving for molarity.
Molarity (M) = 0.43 mol NaCl solute / 0.250 L solution = 1.7 M NaCl (original solution)
2. Solve for the molarity of the final (diluted) solution.
Remember that the amount of solute remains constant in a dilution problem; it is just the total volume of the solution that changes due to the addition of solvent.
Molarity (M) = 0.43 mol NaCl solute / 1.2 L solution
Molarity (M) of the final solution = 0.36 M NaCl
I hope this helped:))
