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raketka [301]
3 years ago
5

If 54 g of Al reacted with 160 g of O2, find out the weight of product​

Chemistry
1 answer:
Oxana [17]3 years ago
4 0

Answer:

number of Al atom =54÷27=2atom of Al. number of o atom = 160÷16=10 atom of o . =214U MASS of ALO2.

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The reaction below shows how silver chloride can be synthesized.
Vesna [10]
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mole ration of AgCl _{(aq)}  :  AgNO_{3} _{(aq)} =  1 : 1

∴ if moles of  AgNO_{3} _{(aq)} =  15.0 mol
then   "      "     AgCl _{(aq)}  =  15.0 mol

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5 0
3 years ago
Read 2 more answers
Consider the reaction 2CO * O2 —> 2 CO2 what is the percent yield of carbon dioxide (MW= 44g/mol) of the reaction of 10g of c
Arturiano [62]

Answer:

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Explanation:

Hello there!

In this case, for the given chemical reaction whereby carbon dioxide is produced in excess oxygen, it is firstly necessary to calculate the theoretical yield of the former throughout the reacted 10 grams of carbon monoxide:

m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO}  *\frac{44gCO_2}{1molCO_2}\\\\ m_{CO_2}^{theoretical}=16gCO_2

Finally, given the actual yield of the CO2-product, we can calculate the percent yield as shown below:

Y=\frac{10g}{16g} *100\%\\\\Y=62.5\%

Best regards!

8 0
3 years ago
How many moles of argon, Ar, are in 1.31×1024 Ar atoms?
ddd [48]

Answer:

2.18 mol Ar.

Explanation:

Hello there!

In this case, according to the definition of mole as the amount of particles of a given substance, it is possible to introduce the Avogadro's number to assert that 1 mole of any element contains 6.022x10²³ atoms; thus, the moles of Ar in the given amount of atoms turns out to be:

1.31x10^{24}Ar atoms*\frac{1molAr}{6.022x10^{23}atoms}\\\\=2.18molAr

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5 0
3 years ago
Scale
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Explanation:

6 0
3 years ago
What scientist explained the theory of atomic structure by relating it to the planetary model?​
bearhunter [10]

Answer: Rutherford

Explanation:

6 0
3 years ago
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