Answer:
Explanation:
The expression for Clausius-Clapeyron Equation is shown below as:
Where,
P is the vapor pressure
ΔHvap is the Enthalpy of Vaporization
R is the gas constant (8.314×10⁻³ kJ /mol K)
c is the constant.
For two situations and phases, the equation becomes:
Given:
= 13.95 torr
= 144.78 torr
= 25°C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (25 + 273.15) K = 298.15 K
= 298.15 K
= 75°C = 348.15 K
So,
Answer:
3.4x10⁻¹⁹J is the energy of the photon
Explanation:
To find the energy of a photon from its frequency we must use the equation:
E = hf
<em>Where E is the energy of the photon in J, our incognite</em>
<em>h is Planck's constant = 6.6262x10⁻³⁴Js</em>
<em>And f is the frequency = 5.2x10¹⁴Hz = 5.2x10¹⁴s⁻¹</em>
<em />
Replacing:
E = 6.6262x10⁻³⁴Js*5.2x10¹⁴s⁻¹
E = 3.4x10⁻¹⁹J is the energy of the photon
<em />
Answer: the new pressure will be 300mmHg
Explanation:
V1 = 30L.
V2 = 50L
P1 = 500mmHg
P2 =?
P1V1 = P2V2
30 x 500 = P2 x 50
P2 = (30 x 500) / 50
P2 = 300mmHg
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Insulator! I hope this helps! Pls mark mine the brainliest;)
