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mars1129 [50]
3 years ago
10

Cube A and Cube B are similar solids. the volume of cube A is 27 cubic inches , and the volume of cube B is 125 cubic inches. ho

w many times larger is the base area of cube b than the base area of cube A?

Mathematics
2 answers:
spin [16.1K]3 years ago
7 0

Answer:

A.  \frac{25}{9}

Step-by-step explanation:

We have been given that Cube A and Cube B are similar solids. The volume of cube A is 27 cubic inches, and the volume of cube B is 125 cubic inches. We are asked to find the the number of times the base area of cube b is larger than the base area of cube A.

We know that volume of cube with each side of x units is equal to x^3.

First of all, we will find the each side of cube A and B as:

A^3=27

\sqrt[3]{A^3} =\sqrt[3]{27}

A=3

B^3=125

\sqrt[3]{B^3} =\sqrt[3]{125}

B=5

Now, we will find base area of both cubes as:

\frac{\text{Base area of cube B}}{\text{Base area of cube A}}=\frac{B^2}{A^2}

\frac{\text{Base area of cube B}}{\text{Base area of cube A}}=\frac{5^2}{3^2}

\frac{\text{Base area of cube B}}{\text{Base area of cube A}}=\frac{25}{9}

Therefore, the base area of cube B is \frac{25}{9} times larger than the base area of cube A.

Norma-Jean [14]3 years ago
3 0
The answer should be C because that’s the most reasonable and because you can’t simplify 125/7
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\sum_{i=1}^n y^2_i =152^2 + 48^2 + 22^2 + 35^2 + 43^2 + 171^2 + 13^2 + 185^2 + 25^2=93226

\sum_{i=1}^n x_i y_i =50*152+ 55*48+ 50*22+ 79*35+ 44*43+ 37*171+ 70*13+ 45*185+ 49*25=32784

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b=\bar y -m \bar x=77.1111111-(-2.95836*53.22222222)=234.56159

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y=-2.95836 x +234.56159

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brainly.com/question/13458632

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