Question

Cube A and Cube B are similar solids. the volume of cube A is 27 cubic inches , and the volume of cube B is 125 cubic inches. how many times larger is the base area of cube b than the base area of cube A?

Answer 1

Answer:

A.  $\frac{25}{9}$

Step-by-step explanation:

We have been given that Cube A and Cube B are similar solids. The volume of cube A is 27 cubic inches, and the volume of cube B is 125 cubic inches. We are asked to find the the number of times the base area of cube b is larger than the base area of cube A.

We know that volume of cube with each side of $x$ units is equal to $x^3$.

First of all, we will find the each side of cube A and B as:

$A^3=27$

$\sqrt[3]{A^3} =\sqrt[3]{27}$

$A=3$

$B^3=125$

$\sqrt[3]{B^3} =\sqrt[3]{125}$

$B=5$

Now, we will find base area of both cubes as:

$\frac{\text{Base area of cube B}}{\text{Base area of cube A}}=\frac{B^2}{A^2}$

$\frac{\text{Base area of cube B}}{\text{Base area of cube A}}=\frac{5^2}{3^2}$

$\frac{\text{Base area of cube B}}{\text{Base area of cube A}}=\frac{25}{9}$

Therefore, the base area of cube B is $\frac{25}{9}$ times larger than the base area of cube A.

Answer 2

The answer should be C because that’s the most reasonable and because you can’t simplify 125/7