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3 years ago

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Cube A and Cube B are similar solids. the volume of cube A is 27 cubic inches , and the volume of cube B is 125 cubic inches. ho

w many times larger is the base area of cube b than the base area of cube A?

2 answers:

spin [16.1K]3 years ago

7 0

Answer:

A. $\frac{25}{9}$

Step-by-step explanation:

We have been given that Cube A and Cube B are similar solids. The volume of cube A is 27 cubic inches, and the volume of cube B is 125 cubic inches. We are asked to find the the number of times the base area of cube b is larger than the base area of cube A.

We know that volume of cube with each side of $x$ units is equal to $x^3$ .

First of all, we will find the each side of cube A and B as:

$A^3=27$

$\sqrt[3]{A^3} =\sqrt[3]{27}$

$A=3$

$B^3=125$

$\sqrt[3]{B^3} =\sqrt[3]{125}$

$B=5$

Now, we will find base area of both cubes as:

$\frac{\text{Base area of cube B}}{\text{Base area of cube A}}=\frac{B^2}{A^2}$

$\frac{\text{Base area of cube B}}{\text{Base area of cube A}}=\frac{5^2}{3^2}$

$\frac{\text{Base area of cube B}}{\text{Base area of cube A}}=\frac{25}{9}$

Therefore, the base area of cube B is $\frac{25}{9}$ times larger than the base area of cube A.

Norma-Jean [14]3 years ago

3 0

The answer should be C because that’s the most reasonable and because you can’t simplify 125/7

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Step-by-step explanation:

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$\sum_{i=1}^n y_i =152+ 48+ 22+ 35+ 43+ 171+ 13+ 185+ 25=694$

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$b=\bar y -m \bar x=77.1111111-(-2.95836*53.22222222)=234.56159$

So the line would be given by:

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