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IRISSAK [1]
2 years ago
7

Which of these is an example of qualitative observation?

Physics
2 answers:
Zanzabum2 years ago
4 0
Iron nails are attracted to the magnet
melomori [17]2 years ago
4 0

Answer:

B. Iron nails are attracted to the magnet

Explanation:

A <em>qualitative observation</em> is an observation that gives <em>qualitative data </em>-as opposed to quantitative-. This means that the data is non-numerical (or <u>unquantifiable</u>). In other words it could be said that a qualitative observation can be reached when you don't count anything. In chemistry qualitative observations can be made of properties such as color, smell, or whether or not a species is attracted to a magnet.

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A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9
Andreyy89

Answer:

d = 0.0306 m

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

U + K = constant

\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0

7.05 + 30.5 = \frac{0.266}{r}

r = 7.08 \times 10^{-3} m

so distance moved by the particle is given as

d = r_1 - r_2

d = 0.0377 - 0.00708

d = 0.0306 m

6 0
3 years ago
If your prediction turns out to be false your experiment has been a failure
nikdorinn [45]

This is false. Your hypothesis, or prediction, is just that: a prediction. Saying its a failure will result in bias.

3 0
3 years ago
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What are the answers to the question
Vitek1552 [10]

Answer: the link isnt loading

7 0
2 years ago
What can be found in a compost bin?
BigorU [14]
D. all of the above

Hope this helps!
5 0
3 years ago
Read 2 more answers
An electron moves with velocity v⃗ =(5.8i−6.7j)×104m/s in a magnetic field B⃗ =(−0.81i+0.60j)T.
Minchanka [31]

Answer:

Fₓ = 0,  F_{y} = 0  and  F_{z}<em> = - 3.115 10⁻¹⁵   N</em>

Explanation:

The magnetic force given by the expression

       F = q v xB

the bold are vectors,  the easiest analytical way to determine this force in solving the determinant

   F = q \left[\begin{array}{ccc}i&j&k\\5.8&-6.7&0\\-0.81&0.6&0\end{array}\right]  10^{4}

   F = 1.6 10⁻¹⁵ [ i( 0-0) + j (0-0) + k^( 5.8 0.60 - 0.81 67) ]

   F =i^0 + j^0   - k^  3.115 10⁻¹⁵   N

   

Fₓ = 0

F_{y} = 0

F_{z}<em> = - 3.115 10⁻¹⁵   N</em>

6 0
3 years ago
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