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Marrrta [24]
3 years ago
14

When object A collides with object B and bounces back, its final momentum is ____ its initial momentum.

Physics
2 answers:
WARRIOR [948]3 years ago
8 0

Answer : (D) " in the opposite direction of "

Explanation :

It is given that when object A collides with object B and bounces back. This shows that the collision is elastic. There are two conditions for elastic collision :

(1) The momentum remains conserved

(2) Kinetic energy is conserved.

We know that momentum is defined as the product of mass and velocity. After bouncing back, the direction of velocity gets changed. So, the final momentum is in the opposite direction of its initial momentum.

So, the correct option is (D).

Ymorist [56]3 years ago
3 0
When object A collides with object B and bounces back, its final momentum is in the opposite direction of its initial momentum. The correct option among all the options that are given in the question is the last option or option "d". This type of collision is elastic in nature as the ball bounces back and so the momentum has to be in the opposite direction of the initial momentum. <span />
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Find the momentum (in kg.m/s) of a helium nucleus having a mass of 6.68 x 10^-27 kg that is moving at 0.386c.
igomit [66]

Answer:

7.73544\times 10^{-21}kgm/sec

Explanation:

We have given mass of helium nucleus m=6.68\times 10^{-27}kg

Velocity of helium nucleus v=0.386c=0.386\times 3\times 10^{8}m/sec=1.158\times 10^{8}m/sec

Momentum of the helium nucleus is given by P=mv where m is mass and v is velocity

So P=mv=6.68\times 10^{-27}\times 1.158\times 10^{8}=7.73544\times 10^{-21}kgm/sec

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3 years ago
On a spending spree in Malaysia, you buy an ox with a weight of 28.9 piculs in the local unit of weights: 1 picul = 100 gins, 1
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Answer:

1747.41 kg

Explanation:

If          1 piculs = 100 gins,

Then     28.9 piculs = (28.9 × 100) gins = 2890 gins.

Also,

If         1 gin = 16 tahils

then   2890 gins =( 16 × 2890 ) = 46240 tahils

Also,

If         1 tahil = 10 chees,

Then    46240 tahils = 46240 × 10 chees = 462400 chees.

Also,

If           1 chee = 10 hoons

Then      462400 chees =( 10 × 462400) hoons = 4624000 hoons.

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If            1 hoon = 0.3779 g,

Then     4624000 hoons = 0.3779 × 4624000 = 1747409.6 g.

The mass in kg that i will declare in the shipping manifest = (1747409.6/100 )kg = 1747.41 kg

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2 years ago
A moderate force will break an egg. However, an egg droppedon the road usually breaks while one dropped on the grass usuallydoes
Fed [463]

Answer:

C. the time interval for stopping is greater.

Explanation:

As the egg falls onto the grass, it takes a a greater amount of time for it to stop, and thus the force that is being applied to it is in increments; there is never enough force applied on the egg for it to break. That's why the egg doesn't break when it lands on the grass.

In contrast, when the egg is dropped on the road, <em>all of the force that is being applied by the road on the egg is in the tiny interval when the egg touches the road</em>, That force is large enough to break the egg because it is being applied in a tiny amount of time. That's why the egg dropped on the road breaks.

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