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Marrrta [24]
3 years ago
14

When object A collides with object B and bounces back, its final momentum is ____ its initial momentum.

Physics
2 answers:
WARRIOR [948]3 years ago
8 0

Answer : (D) " in the opposite direction of "

Explanation :

It is given that when object A collides with object B and bounces back. This shows that the collision is elastic. There are two conditions for elastic collision :

(1) The momentum remains conserved

(2) Kinetic energy is conserved.

We know that momentum is defined as the product of mass and velocity. After bouncing back, the direction of velocity gets changed. So, the final momentum is in the opposite direction of its initial momentum.

So, the correct option is (D).

Ymorist [56]3 years ago
3 0
When object A collides with object B and bounces back, its final momentum is in the opposite direction of its initial momentum. The correct option among all the options that are given in the question is the last option or option "d". This type of collision is elastic in nature as the ball bounces back and so the momentum has to be in the opposite direction of the initial momentum. <span />
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A newly discovered planet has a mean radius of 7380 km. A vehicle on the planet\'s surface is moving in the same direction as th
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Answer:

292796435 seconds ≈ 300 million seconds

Explanation:

First of all, the speed of the car is 121km/h = 33.6111 m/s

The radius of the planet is given to be 7380 km = 7380000 m

From the relationship between linear velocity and angular velocity i.e., v=rw, the angular velocity of the car will be w=v/r = 33.6111/7380000 = 0.000000455 rad/s = 4.55 x 10⁻⁶ rad/sec

If the angular velocity of the vehicle about the planet's center is 9.78 times as large as the angular velocity of the planet then we have

w(vehicle) = 9.78 x w(planet)

w(planet) = w(vehicle)/9.78 = 4.55 x 10⁻⁶ / 9.78 = 4.66 x 10⁻⁷ rad/sec

To find the period of the planet's rotation; we use the equation

w(planet) = 2π÷T

Where w(planet) is the angular velocity of the planet and T is the period

From the equation T = 2π÷w = 2×(22/7) ÷  4.66 x 10⁻⁷ = 292796435 seconds

Therefore the period of the planet's motion is 292796435 seconds which is approximately 300, 000, 000 (300 million) seconds

8 0
3 years ago
A person takes a trip, driving with a constant speed of 99.5 km/h, except for a 26.0-min rest stop. The person's average speed i
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Answer:

1.65 h

121.39 km

Explanation:

Given that

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Average speed of the driver = 73.6 km/h

check attachment for calculation and how I arrived at the answer

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2 years ago
If you have a yellow sheet of paper and shine a cyan light what color is the paper
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A 0.50-kg object moves in a horizontal circular track with a radius of 2.5 m. An external forceof 3.0 N, always tangent to the t
kodGreya [7K]

The work done by the force is 47.1 J

Explanation:

The work done by a force in moving an object is given by

W=Fd cos \theta (1)

where

F is the magnitude of the force

d is the distance covered by the object

\theta is the angle between the direction of the force and the motion of the object

In this problem, the force applied to the object is

F = 3.0 N

This force is always tangential to the track: this means that at every instant, the force is parallel to the motion of the object, so

\theta=0

And the distance covered is equal to the circumference of the circle, which is:

d=2\pi r=2\pi (2.5 m)=15.7 m

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Now we can substitute into eq.(1) to find the work done:

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Learn more about work:

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How does vacuum reduce thermal energy transfer
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